Answer:
See the explanation.
Step-by-step explanation:
Condition A.
A rectangle with four right angles
There can be many quadrilaterals satisfying this condition.
Condition B.
A square with one side measuring 5 inches
There can be only one quadrilateral satisfying this condition.
Condition C.
A rhombus with one angle measuring 43°
There can be many quadrilaterals satisfying this condition.
Condition D.
A parallelogram with one angle measuring 32°
There can be many quadrilaterals satisfying this condition.
Condition E.
A parallelogram with one angle measuring 48° and adjacent sides measuring 6 inches and 8 inches.
There can be only one quadrilateral satisfying this condition.
Condition F.
A rectangle with adjacent sides measuring 4 inches and 3 inches.
There can be only one quadrilateral satisfying this condition.
(Answer)
1. 4 5.-22 9.-60 13.-85
2.-7 6.-33 10.33 14.-21
3.-36 7.87 11.-78 15.-23
4. 78 8.55 12.24 16.149
Answer:
Step-by-step explanation:
b = 2/3
a = 7/3
b)
Cross multiply,
2b + 1 = a*(3b - 1)
2b + 1 = a*3b - 3*a
2b + 1 = 3ab- 3a
2b = 3ab - 3a - 1
2b - 3ab = -3a - 1
b(2 - 3a) = -3a - 1
We know that:
Mean = 82 mm and SD = 10 mm ( standard deviation )
82 - 3 * SD = 82 - 3 * 10 = 82 - 30 = 52 mm
82 + 3 * SD = 82 + 3 * 10 = 82 + 30 = 112 mm
Population between 52 and 112 mm is within +/- 3 standard deviations from the mean.
By the 66- 95 - 99.7 % rule it is: 99.7% of the test group.
0.977 * 500 = 498.5
Answer:
99.7 % of the test group have a diastolic pressure between 52 and 112 mm, or 498 men.
