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mash [69]
3 years ago
5

janice invests a total of 8000 in two different accounts. the first account returns 5%, while the second account returns 8%. if

the total interest earned after one year is 565, what principal did she invest in each account?​
Mathematics
1 answer:
Zinaida [17]3 years ago
6 0

Answer:

"She invested $2500 in 5% account and $5500 in 8% account"

Step-by-step explanation:

Let the amount invested in 5% account be "x"

So, the amount invested in 8% account would be "8000 - x"

Interest amount is the percentage multiplied by amount invested. So

Interest of 5% account = 5% of x = 0.05x

Interest of 8% account = 8 % of 8000 - x = 0.08(8000 - x)

Total interest is the sum of these 2 expressions that EQUATES to 565 (given). Let's solve for x:

0.05x + 0.08(8000 - x) = 565\\0.05x+640-0.08x=565\\0.03x=75\\x=2500

and thus,

"8000 - x" = 8000 - 2500 = 5500

Hence,

She invested $2500 in 5% account and $5500 in 8% account

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Last year, a women's professional organization made two small-business loans totaling $28,000 to young women beginning their own
igor_vitrenko [27]

Answer:

$7,000 at a rate of 7% and $21,000 at a rate of 14%.

Step-by-step explanation:

Let x be amount invested at 7% and y be amount invested at 14%.

We have been given that a women's professional organization made two small-business loans totaling $28,000. We can represent this information in an equation as:

x+y=28,000...(1)

The interest earned at 7% in one year would be 0.07x and interest earned at 14% in one year would be 0.14x.

We are also told that the organization received from these loans was $3,430. We can represent this information in an equation as:

0.07x+0.14y=3,430...(2)

Form equation (1), we will get:

x=28,000-y

Upon substituting this value in equation (2), we will get:

0.07(28,000-y)+0.14y=3,430

1960-0.07y+0.14y=3,430

1960+0.07y=3,430

1960-1960+0.07y=3,430-1960

0.07y=1470

\frac{0.07y}{0.07}=\frac{1470}{0.07}

y=21,000

Therefore, an amount of $21,000 was invested at a rate of 14%.

x=28,000-y

x=28,000-21,000

x=7,000

Therefore, an amount of $7,000 was invested at a rate of 14%.

8 0
3 years ago
Question 12
soldi70 [24.7K]

The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

The tank for a car holds 17 gallons. The gasoline gauge shows the tank is 3/4 full. How much gas is still in the tank?

Give your answer as a whole number or as a mixed fraction reduced to lowest terms.

Answer:

Gas \: \:left = 12 \frac{3}{4} \: \:gallons \\\\

Step-by-step explanation:

The tank for a car holds 17 gallons.

The gasoline gauge of the car shows that the tank is 3/4 full.

We are asked to find the remaining gasoline in the tank.

Gas \: \:left = \frac{3}{4} \times 17 \\\\Gas \: \:left = \frac{51}{4}  \\\\Gas \: \:left = 12 \frac{3}{4}  \: \:gallons \\\\

Therefore, the remaining gas in the tank is 12\frac{3}{4} gallons.

Alternatively:

1 - \frac{3}{4}  = \frac{1}{4}

Amount of gasoline consumed = \frac{1}{4} \times 17 =  \frac{17}{4}

Amount of gasoline left = total - consumed

Amount of gasoline left = 17 - \frac{17}{4} = 12\frac{3}{4} \:\: gallons

6 0
3 years ago
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