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earnstyle [38]
3 years ago
9

0/1

Mathematics
2 answers:
emmainna [20.7K]3 years ago
7 0

Answer:

its C

Step-by-step explanation:

but aye shorty how old are you

ser-zykov [4K]3 years ago
5 0

Answer:

idk I think it a idk good luck tho hope u get a better answer

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Fraction in simplest form
nataly862011 [7]

Answer:

14/15 meters

Step-by-step explanation:

We add each color of fabric to find the total amount of fabric used.

1/3 +3/5

We need to get a common denominator of 15

1/3 *5/5 = 5/15

3/5*3/3 = 9/15

5/15 + 9/15 = 14/15

5 0
3 years ago
Read 2 more answers
Find the measure of each marked angle!!
tamaranim1 [39]

Answer:

60 is the answer

Step-by-step explanation:

10x - 20 = 7x + 4 (Corresponding angles)

10x - 7x = 20 + 4

3x = 24

x = 8

substituting the values,

10(8) - 20

80 - 20

60

similarly the other angle is 60 since they are corresponding angles.

8 0
3 years ago
Help please<br>Mark as brainliest
34kurt
You need to use this formula:
([a]/[sinA])=([c]/[sinC])-I am going to use 'a' for the x, and 'c' for 16(square root of 3)
Now its just getting 'a' by itself.
([c] times [sinA])/([sinC])=[a]
[c]=16 square root of 3
sinA=sin(60)=(square root of 3)/2
sinC=sin(90)=1

Plug it in to get 24 for a, or x. Do the same to figure out y with the new sides.
The final y is:
8 square root of 3
Final answer is C.
8 0
3 years ago
If Breanna drives a constant speed for 3 hours and travels 180 miles, what is her speed a mile per hour
Georgia [21]

Answer:

60 mph

Step-by-step explanation:

You divide 180 by 3 to get 60 mph

3 0
3 years ago
If a fire is burning a building and it takes 2 hours to put it out using 2000 gal./min., what minimum diameter cylindrical tank
strojnjashka [21]

Answer:

The minimum diameter of the cylindrical tank needed to store the quantity needed to put out the fire is approximately 58.415 feet.

Step-by-step explanation:

A gallon equals 0.134 cubic feet. First, we determine the amount of water (Q), measured in cubic feet, needed to put out the fire under the assumption that water is consumed at constant rate:

Q = \dot Q \cdot \Delta t (1)

Where:

\dot Q - Volume rate, measured in feet per minute.

\Delta t - Time, measured in minutes.

If we know that \dot Q = 2000\,\frac{gal}{min} and \Delta t = 120\,min, then the amount of water is:

Q = \left(2000\,\frac{gal}{min} \right)\cdot (120\,min) \cdot \left(0.134\,\frac{ft^{3}}{gal} \right)

Q = 32160\,ft^{3}

And the diameter of the cylindrical tank based on the capacity found above is determined by volume formula for a cylinder:

Q = \frac{\pi}{4}\cdot D^{2}\cdot h (2)

Where:

D - Diameter, measured in feet.

h - Height, measured in feet.

If we know that Q = 32160\,ft^{3} and h = 12\,ft, then the minimum diameter is:

D^{2} = \frac{4\cdot Q}{\pi\cdot h}

D = 2\cdot \sqrt{\frac{Q}{\pi\cdot h} }

D = 2\cdot \sqrt{\frac{32160\,ft^{3}}{\pi\cdot (12\,ft)} }

D \approx 58.415\,ft

The minimum diameter of the cylindrical tank needed to store the quantity needed to put out the fire is approximately 58.415 feet.

8 0
3 years ago
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