Mode = 2
hope it helps
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If we expand bx to jx and kx we have:
5y^2-2y-7
5y^2-7y+5y-7 then factor...
y(5y-7)+1(5y-7)
(y+1)(5y-7)
So the other factor is:
(y+1)
Number 3 is 1/6 to role a 1 on the second roll is 1/36= 1/6 X 1/6
to get 2 on the third role is 1/216 so the probability is 1/216
Answer:
B: x=-1
Step-by-step explanation:
5x+6=1
5x+6-6=1-6
simplify
divide by 5 on both sides
x=-1
