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lisabon 2012 [21]
3 years ago
12

Prompt:

Mathematics
2 answers:
Varvara68 [4.7K]3 years ago
8 0

Answer:

x power2+6x+4 is the answer

Oksana_A [137]3 years ago
6 0

Answer:

okay here we go ,

in multiplication of polynomials, we have to multiply each term of first polynomial to each term of the second polynomial.

So,

=》

(x + 2)(x - 4)

now, multiply x in first polynomial to both terms of second polynomial and add them, similarly multiply 2 with both terms of second polynomial and add them .

=》

(x \times x) + (x \times  - 4) + (2 \times x) + (2 \times  - 4)

=》

{x }^{2}  + ( -4x) + 2x + ( - 8)

now, add them up : -

=》

{x}^{2}  - 4x + 2x  - 8

now, check for like terms, if there are like terms then combine them.

( here like terms are -4x and +2x )

we get,

=》

{x}^{2}  - 2x - 8

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Which expression is eqivalent to 10c - 6c + 3 + 7d + 12 + 4d?
vesna_86 [32]

Answer:

d. 4c + 11d + 15

Step-by-step explanation:

This is a pretty simple combining like terms problem.

10c - 6c = 4c

3 + 12 = 15

7d + 4d = 11d

Therefore, our expression will be 4c + 11d + 15.

6 0
3 years ago
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A function g models a relationship in which the dependent variable is multiplied by 4 for every 2 units the independent variable
12345 [234]
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Consider the sequence of numbers: 3/8, 3/4, 1 /18, 1 1/2, 1 7/8
vredina [299]

Question:

Consider the sequence of numbers: \frac{3}{8}, \frac{3}{4}, 1\frac{1}{8}, 1\frac{1}{2}, 1\frac{7}{8}

Which statement is a description of the sequence?

(A) The sequence is recursive, where each term is 1/4 greater than its preceding term.

(B) The sequence is recursive and can be represented by the function

f(n + 1) = f(n) + 3/8 .

(C) The sequence is arithmetic, where each pair of terms has a constant difference of 3/4 .

(D) The sequence is arithmetic and can be represented by the function

f(n + 1) = f(n)3/8.

Answer:

Option B:

The sequence is recursive and can be represented by the function

f(n + 1) = f(n) + \frac{3}{8}  .

Explanation:

A sequence of numbers are

\frac{3}{8}, \frac{3}{4}, 1\frac{1}{8}, 1\frac{1}{2}, 1\frac{7}{8}

Let us first change mixed fraction into improper fraction.

\frac{3}{8}, \frac{3}{4}, \frac{9}{8}, \frac{3}{2}, \frac{15}{8}

To find the pattern of the sequence.

To find the common difference between the sequence of numbers.

\frac{3}{4}-\frac{3}{8}=\frac{6}{8}-\frac{3}{8}= \frac{3}{8}

\frac{9}{8}-\frac{3}{4}=\frac{9}{8}-\frac{6}{8}= \frac{3}{8}

\frac{3}{2}-\frac{9}{8}=\frac{12}{8}-\frac{9}{8}= \frac{3}{8}

\frac{15}{8}-\frac{3}{2}=\frac{15}{8}-\frac{12}{8}= \frac{3}{8}

Therefore, the common difference of the sequence is 3.

That means each term is obtained by adding \frac{3}{8} to the previous term.

Hence, the sequence is recursive and can be represented by the function f(n + 1) = f(n) + \frac{3}{8}  .

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Step-by-step explanation:

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