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3 years ago

It is commonly believed that the mean body temperature of a healthy adult is

Mathematics

1 answer:

GuDViN [60]3 years ago

3 0

Answer:

It is commonly believed that the mean body temperature of a healthy adult is

98.6

∘

98.6

∘

F. You are not entirely convinced. You believe that it is not

98.6

∘

98.6

∘

F. You collected data using 35 healthy people and found that they had a mean body temperature of

98.22

∘

98.22

∘

F with a standard deviaiton of

1.06

∘

1.06

∘

F. Use a 0.05 significance level to test the claim that the mean body temperature of a healthy adult is not

98.6

∘

98.6

∘

Step-by-step explanation:

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3 years ago

The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e

Korolek [52]

Answer:

A sample of 499 is needed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is given by:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

In this question, we have that:

$\pi = 0.21$

90% confidence level

So $\alpha = 0.1$ , z is the value of Z that has a pvalue of $1 - \frac{0.1}{2} = 0.95$ , so $Z = 1.645$ .

How large a sample would be required in order to estimate the fraction of tenth graders reading at or below the eighth grade level at the 90% confidence level with an error of at most 0.03

We need a sample of n, which is found when $M = 0.03$ . So