The table containing the data needed for this problem is attached on this answer. This data is used to determine the best fit line that is extracted from this multitude of points given. Best fit line is described as a line in which the variation of each point to the line is the minimum. We plot the data using MS Excel and is shown in the figure attached as well. We determine the trendline of the graph by the function in MS Excel. The equation of the trendline is expressed as <span>y = -26.059x + 722.63 in which the coefficient of determination, r^2 = 0.8947. </span>
Answer:
176
Step-by-step explanation:
88% = 88/100
88 × 2 = 176
176/200
1: always rearrange the equation to y = mx + c so....
x - y = o
x = y
So the gradient is 1 and it intersects the y axis at (0,0)
The three points could be (1,1), (2,2), (3,3) and so on
2: -x -2y = -10
Multiply everything by -1
x + 2y = 10
2y = 10 - x
y = 5 - x/2
The y intercept is 5 so you could use the point (0,5), (2,4), (4,3) and so on
3: x + y = -2
y = -2 - x
The y intercept is -2 so you could use the points (0,-2), (2,-4), (3,-5) and so on
4: -3y =-x -7
Multiply everything by -1
3y = x + 7
y = x/3 + 7/3
The y intercept is 7/3 so you could use the points (0,7/3), (3,10/3), (6,13/3) and so o
5: -y = -x + 1
y = x - 1
The y intercept is -1 so you could use the points (0,-1), (2,1), (3,2) and so on
Hope this helps! Any questions let me know :)
Answer:
392π
Step-by-step explanation:
Equation is 1/3(piR^2)*h
Radius is 7, 7 squared is 49.
1/3(49π)(24)
392π
1 kilometer= 1000 meters
3x1000= 3000 meters
3000/ 25= 120 pool lengths
