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3 years ago

What is one condition that must be met for a population to be in genetic equilibrium?

Biology

2 answers:

storchak [24]3 years ago

7 0

Answer:

B. There is no genetic drift.

Explanation:

For a population to be in genetic balance it is necessary that, in this population, no genetic drift occurs. This can be explained through the Hardy-Weinberg balance.

According to the Hardy-Weinberg balance, for a population to reach genetic equilibrium, it is necessary that mutations do not occur in this population, natural selection does not occur, does not occur, does not occur gene flow, occurs random crosses and no genetic drift occurs.

Genetic drift is a term used to describe a suture that causes a strong change in the genotype of a population, resulting in a low genetic variability among individuals that will have to undergo selection pressure.

masha68 [24]3 years ago

6 0

The answer should be (C)

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Here is a hypothetical situation: An area of the country has received a record amount of rainfall this year coupled with a mild

Ronch [10]

Answer:

Zika virus and West Nile virus are the two pathogens which causes more diseases due to increase the population of mosquito.

Explanation:

Zika virus belongs to the family of Flaviviridae. Aedes mosquitoes which are active at day time are the carrier of this virus. West Nile virus is also spread through the bite of mosquito. The infected mosquito is the main cause of spreading of this disease. This virus is spreading too fast in the United States of America in the summer season where the population of mosquitoes increases.

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3 years ago

The Offspring produced by a cross between two given types of plants can be any of the three genotypes denoted by A, B, and C. A

ratelena [41]

Complete question:

The offspring produced between two given types of plants can be any of the three genotypes, denoted by A, B and C. A theoretical model of gene inheritance suggests that the offspring of types A, B and C should be in a 1:2:1 ratio (meaning 25% A, 50% B, and 25% C). For experimental verification, 100 plants are bred by crossing the two given types. Their genetic classifications are recorded in the table below.

Genotype Observed frequency

A → 18 individuals

B → 55 individuals

C → 27 individuals

Do these contradict the genetic model?

Use a 0.05 level of significance.

Determine the chi-square test statistic.

Answer:

Do these contradict the genetic model? No, according to the chi-square test, there is not enough evidence to reject the null hypothesis of the population being in equilibrium.

Explanation:

Available data:

Crossed genotypes: two
Genotypes among the offspring; Three → A, B, and C
Expected phenotypic ratio → 1:2:1
Total number of individuals, N = 100
A = 18 individuals
B = 55 individuals
C = 27 individuals

So, let us first state the hypothesis:

H₀= the population is equilibrium for this locus → F(A) = 25%, F(B) = 50%, F(C) = 25%
H₁ = the population is not in equilibrium

Now, let us calculate the number of expected individuals, according to their expected ratio.

4 -------------- 100% -------------100 individuals

1 --------------- 25% -------------X = 25 individuals A

2 -------------- 50% -------------X = 50 individuals B

1----------------- 25%--------------X = 25 individuals C

A B C

Observed 18 55 27
Expected 25 50 25
(Obs-Exp)²/Exp 1.96 0.5 0.16

(Obs-Exp)²/Exp

A) (18 - 25)²/25 = 49/25 = 1.96

B) (55 - 50)² / 50 = 25/50 = 0.5

C) (27 - 25)²/25 = 4/25 = 0.16

Chi square = X² = Σ(Obs-Exp)²/Exp

∑ is the sum of the terms
O are the Observed individuals: 2 in chamber B, and 18 in chamber A.
E are the Expected individuals: 10 in each chamber

X² = ∑ ((O-E)²/E) = 1.96 + 0.5 + 0.16 = 2.62

Freedom degrees = 2

Significance level, 5% = 0.05

Table value/Critical value = 5.99

X² < Critical value

2.62 < 5.99

These results suggest that there is not enough evidence to reject the null hypothesis. We can assume that the locus under study in this population is in equilibrium H-W.

6 0

3 years ago

Alan is a 47-year-old man who has no documentation of a primary series of tetanus-containing vaccine. Which of the following wou

Brrunno [24]

Answer:

Option D, Tdap today; Td in 4 weeks; Td 6 months after the second dose

Explanation:

In general, Tdap is given before Td to all those adults who have never been administered with Tdap earlier.

Also as per the publication of CDC, any individual who is of 7 years or older than this and has never been vaccinated by Td needs following schedule of medication

a) First primary dose

b) After the first primary dose the second primary dose of Td must be given in 4 weeks and

c) The third primary dose must be given after 6 to 12 months.

Hence, option D is correct

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3 years ago

Which of the following is true regarding scientific theories,laws, and knowledge?

stepladder [879]

I would say d I’m probably wrong , I hope this helps (:

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3 years ago

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aliya0001 [1]

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