Question

Truck A leaves station 1 at 9:00 a.m. and travels at the rate of 60 kph. After 2 hours, Truck B leaves the same station and travels in the same direction at the rate of 80 kph. At what time will Truck B overtake Truck A?

Answer 1

Answer: $5:00\ PM$

Step-by-step explanation:

Given

Truck A speed is $v_a=60\ kmph$

Truck B speed is $v_b=80\ kmph$

Truck A leaves 2 hours before truck B

Distance traveled in the 2 hour

$\Rightarrow 60\times 2=120\ km$

Suppose Truck B will catch truck A after t hours

$\therefore 120+60t=80t$

$\Rightarrow 120=20t\\\Rightarrow t=6\ hr$

Overtake time is $9:00am +2+6=5:00\ PM$