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kotegsom [21]
3 years ago
13

pls help immediately! this is due in 3 mins :/. (pls don’t give a link, i’ll give brainiest for the correct answer just pls help

!)

Mathematics
1 answer:
zavuch27 [327]3 years ago
6 0

Answer:

50 i think but i'm not 100 % sure i'm sorry

Step-by-step explanation:

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infinite many solutions

Step-by-step explanation:

  • 5(2(b)+1) = 10(b) + 5
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<u>As L.H.S = R.H.S, there are infinite many solutions</u>

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Suppose that the times required for a cable company to fix cable problems in its customers’ homes are uniformly distributed betw
vampirchik [111]

Answer:

a) 60% probability that a randomly selected cable repair visit will take at least 50 minutes

b) 60% probability that a randomly selected cable repair visit will take at most 55 minutes.

c) The expected length of the repair visit is 52.5 minutes.

d) The standard deviation is 7.22 minutes.

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value X lower than x is given by the following formula.

P(X \leq x) = \frac{x - a}{b-a}

For this problem, we have that:

Uniformly distributed between 40 and 65 minutes, so a = 40, b = 65

(a) What is the probability that a randomly selected cable repair visit will take at least 50 minutes?

Either it takes less than 50 minutes, or it takes at least 50 minutes. The sum of the probabilities of these events is decimal 1. So

P(X < 50) + P(X \geq 50) = 1

The intervals can be open or closed, so

P(X < 50) = P(X \leq 50)

We have that

P(X \geq 50) = 1 - P(X < 50)

P(X < x) = \frac{50 - 40}{65 - 40} = 0.4

P(X \geq 50) = 1 - P(X < 50) = 1 - 0.4 = 0.6

60% probability that a randomly selected cable repair visit will take at least 50 minutes

(b) What is the probability that a randomly selected cable repair visit will take at most 55 minutes?

This is P(X \leq 55)

P(X \leq 55) = \frac{55 - 40}{65 - 40} = 0.6

60% probability that a randomly selected cable repair visit will take at most 55 minutes.

(c) What is the expected length of the repair visit?

The mean of the uniform distribution is:

M = \frac{a+b}{2}

So

M = \frac{40+65}{2} = 52.5

The expected length of the repair visit is 52.5 minutes.

(d) What is the standard deviation?

The standard deviation of the uniform distribution is

S = \sqrt{\frac{(b-a)^{2}}{12}}

So

S = \sqrt{\frac{(65-40)^{2}}{12}}

S = 7.22

The standard deviation is 7.22 minutes.

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3 years ago
What is the expression equivalent to 64 - x^2
Murrr4er [49]

Answer: -(x+8)(x-8)

Step-by-step explanation:

-(x^2-64)

x^2-8^2x^2

x^2-8^2=(x+8)(x-8)

-(x+8)(x-8)

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Click the link up there that answer is that
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