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3 years ago

80 POINTS, BRAINLIEST, AND QUESTION IS MULTIPLE CHOICE!!! (please answer quickly)

Physics

2 answers:

victus00 [196]3 years ago

8 0

Answer:

Since gravitational force is inversely proportional to the square of the separation distance between the two interacting objects, more separation distance will result in weaker gravitational forces. So as two objects are separated from each other, the force of gravitational attraction between them also decreases.

When dealing with the force of gravity between two objects, there are only two things that are important – mass, and distance. The force of gravity depends directly upon the masses of the two objects, and inversely on the square of the distance between them.

Explanation:

I could be wrong but I would say B :)

Have a good day!

Gala2k [10]3 years ago

8 0

answer:

i believe the answer is d

explanation:

here's why;

c. is incorrect because everything has a gravitational force.

a. is also incorrect because gravity is what holds the tennis ball down and keeps it on the ground.

i don't really know how to explain why b. is wrong, but d. is the correct answer because the force of friction opposes the motion of an object, causing moving objects to lose energy and slow down.

good luck :)

i hope this helps

**please let me know if this was incorrect**

have a great day !!

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nadezda [96]

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3 years ago

A point charge q1 is at the center of a sphere of radius 20 cm. Another point charge q2 = 10 nC is located at a distance r = 10

jok3333 [9.3K]

Answer:

q₁ = -2.92 nC

Explanation:

Given;

first point charge, q₁ = ?

second point charge, q₂ = 10 nC

net flux through the surface of the sphere, Φ = 800 N.m²/C

According to Gauss’s law, the flux through any closed surface (Gaussian surface), is equal to the net charge enclosed divided by the permittivity of free space.

$\phi = \frac{q_{enc.}}{\epsilon_o}$

where;

Φ is net flux

$q_{enc.}$ net charge enclosed

ε₀ is permittivity of free space.

$q_{enc.}$ = Φε₀

= 800 x 8.85 x 10⁻¹²

= 7.08 x 10⁻⁹ C

$q_{enc.}$ = 7.08 nC

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q₁ = $q_{enc.}$ - q₂

q₁ = 7.08nC - 10 nC

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a_sh-v [17]

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Explanation:

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