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3 years ago

A resistor is connected to an ideal ac power supply. (a) the phase angle between the current and voltage is

Physics

1 answer:

bezimeni [28]3 years ago

6 0

Answer:

0 degrees

Explanation:

A resitor's phase angle between voltage and current is zero. Viewed in the complex plane, resistance has only a real component, its imaginary component is always 0, thus causing no phase shift.

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A car is traveling down the highway at speed 5 m/s when the driver slams on the brakes and skids to a stop in a distance 80 m. A

Murljashka [212]

The car is very incredibly fast

8 0

3 years ago

An automobile traveling along a straight road increases its speed from 72 ft/s to 84 ft/s in 180 ft. if the acceleration is cons

Nikolay [14]

The equation that would allow us to calculate for the acceleration given the distance is written below,

a = (Vf² - Vo²) / 2d

where a is the acceleration, Vf is the final velocity, Vo is the initial velocity, and d is distance.

Substituting the known values,
a = ((84 ft/s)² - (72 ft/s)²) / 2(180 ft) = 5.2 ft/s²

Then, the equation that would relate the initial velocity, distance, acceleration and time is calculated through the equation,

d = Vot + 0.5at²

Substituting the known values,
180 = 72(t) + 0.5(5.2)(t²)

The value of t from the equation is 2.3 s

ANSWER: 2.3 s

5 0

4 years ago

Answer the question below:

Bezzdna [24]

Answer:

D) the decay rates of radioactive uranium and lead

Explanation:

As we know that when she found the substance it must have some fixed ratio of radioactive uranium and Lead in that substance.

Here since Uranium is radioactive substance so it will continuously convert into Lead and this ratio will change with time

So here we can say that the ratio of radioactive uranium and lead will depend on its decay rate

now to find the age of the substance we can find the present ratio of lead and uranium in that substance and then compare it with freshly prepared substance.

so by the formula

we can find the age of the sample

6 0

3 years ago

Read 2 more answers

A proton and an alpha particle (q = +2e, m = 4 u) are fired directly toward each other from far away, each with an initial speed

stich3 [128]

Answer:

Distance of closest approach, $r=1.91\times 10^{-14}\ m$

Explanation:

It is given that,

Charge on proton, $q_p=e$

Charge on alpha particle, $q_a=2e$

Mass of proton, $m_p=1.67\times 10^{-27}\ kg$

Mass of alpha particle, $m_a=4m_p=6.68\times 10^{-27}\ kg$

The distance of closest approach for two charged particle is given by :

$r=\dfrac{k2e^2(m_p+m_a)}{2m_am_pv_p^2}$

$r=\dfrac{9\times 10^9\times 2(1.6\times 10^{-19})^2(1.67\times 10^{-27}+6.68\times 10^{-27})}{2\times 6.68\times 10^{-27}\times 1.67\times 10^{-27}(0.01\times 3\times 10^8)^2}$

$r=1.91\times 10^{-14}\ m$

So, their distance of closest approach, as measured between their centers $1.91\times 10^{-14}\ m$ . Hence, this is the required solution.

4 0

3 years ago

Colonel John P. Stapp, USAF, participated in studying whether a jet pilot could survive emergency ejection. On March 19, 1954, h

PolarNik [594]

Answer:

(a) a = - 201.8 m/s²

(b) s = 197.77 m

Explanation:

(a)

The acceleration can be found by using 1st equation of motion:

Vf = Vi + at

a = (Vf - Vi)/t

where,

a = acceleration = ?

Vf = Final Velocity = 0 m/s (Since it is finally brought to rest)

Vi = Initial Velocity = (632 mi/h)(1609.34 m/ 1 mi)(1 h/ 3600 s) = 282.53 m/s

t = time = 1.4 s

Therefore,

a = (0 m/s - 282.53 m/s)/1.4 s

a = - 201.8 m/s²

(b)

For the distance traveled, we can use 2nd equation of motion:

s = Vi t + (0.5)at²

where,

s = distance traveled = ?

Therefore,

s = (282.53 m/s)(1.4 s) + (0.5)(- 201.8 m/s²)(1.4 s)²

s = 395.54 m - 197.77 m

s = 197.77 m

6 0

3 years ago