Given Information:
Elapsed time = t = 6 seconds
Required Information:
Distance = d = ?
Answer:
Distance = d = 2.058 km
Explanation:
We know that the speed of sound in the air is given by
v = 343 m/s
The relation between distance, speed and time is given by
distance = speed*time
substituting the given values yields,
distance = 343*6
distance = 2058 m
There are 1000 meters in 1 km so
d = 2058/1000
d = 2.058 km
Therefore, the storm is about 2.058 km away when elapse time between the lightning and the thunderclap is 6 seconds.
Based on the calculations, the speed required for this satellite to stay in orbit is equal to 1.8 × 10³ m/s.
<u>Given the following data:</u>
- Gravitational constant = 6.67 × 10⁻¹¹ m/kg²
- Mass of Moon = 7.36 × 10²² kg
- Distance, r = 4.2 × 10⁶ m.
<h3>How to determine the speed of this satellite?</h3>
In order to determine the speed of this satellite to stay in orbit, the centripetal force acting on it must be sufficient to change its direction.
This ultimately implies that, the centripetal force must be equal to the gravitational force as shown below:
Fc = Fg
mv²/r = GmM/r²
<u>Where:</u>
- m is the mass of the satellite.
Making v the subject of formula, we have;
v = √(GM/r)
Substituting the given parameters into the formula, we have;
v = √(6.67 × 10⁻¹¹ × 7.36 × 10²²/4.2 × 10⁶)
v = √(1,168,838.095)
v = 1,081.13 m/s.
Speed, v = 1.8 × 10³ m/s.
Read more on speed here: brainly.com/question/20162935
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<span>A) x = 41t
The classic equation for distance is velocity multiplied by time. And unfortunately, all of your available options have the form of that equation. In fact, the only difference between any of the equations is what looks to be velocity. And in order to solve the problem initially, you need to divide the velocity vector into a vertical velocity vector and a horizontal velocity vector. And the horizontal velocity vector is simply the cosine of the angle multiplied by the total velocity. So
H = 120*cos(70) = 120*0.34202 = 41.04242
So the horizontal velocity is about 41 m/s. Looking at the available options, only "A" even comes close.</span>
Answer:
Velocity, quantity that designates how fast and in what direction a point is moving.
Explanation:
Answer:
lowest frequency = 535.93 Hz
distance between adjacent anti nodes is 4.25 cm
Explanation:
given data
length L = 32 cm = 0.32 m
to find out
frequency and distance between adjacent anti nodes
solution
we consider here speed of sound through air at room temperature 20 degree is approximately v = 343 m/s
so
lowest frequency will be = 
..............1
put here value in equation 1
lowest frequency will be = 
lowest frequency = 535.93 Hz
and
we have given highest frequency f = 4000Hz
so
wavelength = 
..............2
put here value
wavelength = 
wavelength = 0.08575 m
so distance = 
..............3
distance = 
distance = 0.0425 m
so distance between adjacent anti nodes is 4.25 cm
