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Fantom [35]
3 years ago
6

Two isosceles triangles are shown above. If b = 180-4a and a=35, What is the value of c?

Mathematics
1 answer:
Ymorist [56]3 years ago
4 0

Answer:

a=35 given

b=40  

c=110

I couldn't complete see c. Please look at the picture to see what I assumed it to be.

Step-by-step explanation:

Hmmm... I guess a and b are not vertical.

We are given b=180-4a and a=35 so b=180-4(35)=180-140=40.

So b=40.

Isosceles triangles always have congruent base angles.  So let's call both of the base angles in the bottom triangle x.

That means x+x+40=180.

We need to solve this for x.

Combine like terms:

2x+40=180

Subtract 40 on both sides:

2x=140

Divide both sides by 2:

x=140/2

Simplify:

x=70

So I'm assuming that c and it's adjacent angle are sitting on a straightedge together which means 70+c=180.

70+c=180

Subtract 70 on both sides:

c=180-70

Simplify:

c=110

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3 years ago
In parallelogram ABCD, AB = 16 cm, DA = 3<img src="https://tex.z-dn.net/?f=%5Csqrt%7B2%7D" id="TexFormula1" title="\sqrt{2}" alt
Murljashka [212]

Answer:

length of segment YZ is 8 cm

Step-by-step explanation:

given data

AB = 16 cm

DA = 3\sqrt{2} cm

AB and DA form interior angle  =  45-degre

WX ≠ YZ

WX = 16 cm

to find out

length of segment YZ

solution

area of △ABD is  the same as the area of △BCD

and

area of △ABD is express as

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put here value

area of △ABD = 16 × 3√2 × sin(45) ÷ 2

area of △ABD = 24

and

area of the parallelogram is

area of the parallelogram = 24 × 2

area of the parallelogram = 48

so

now we will consider here YZ = x

and Since ZY XW is isosceles trapezoid

so here we can say that

WM = ZM = (16 - x)  ÷ 2   .......................2

so area of  trapezoid will be

area of  trapezoid = \frac{ZY + WX }{2}  \times ZM         .......................3

area of  trapezoid = \frac{x+16}{2} \times \frac{16 - x}{2}    

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solve it we get

x = 8

so length of segment YZ is 8 cm

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Answer:

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Step-by-step explanation:

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Use a graphing calculator.

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