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Wewaii [24]
2 years ago
8

Could someone tell me if I’m right please? WILL GIVE BRAINLIEST!

Mathematics
1 answer:
katrin2010 [14]2 years ago
5 0
Yes you are correct! because there are no values of x that make the equation true.
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The equation for y=-2x+5 that is paralell passes through (1,-4)?
sattari [20]
0 beaxysabahagpannauqqu
6 0
2 years ago
The parallel boxplots below display the quiz grades (out of 30) for two of Mrs. Smith’s statistics classes.
stich3 [128]

Answer:

The quiz grades for class 1 have more variability than the quiz grades for class 2.

Step-by-step explanation:

8 0
3 years ago
How many extraneous solutions does the equation below have? StartFraction 9 Over n squared 1 EndFraction = StartFraction n 3 Ove
BigorU [14]

The equation has one extraneous solution which is n ≈ 2.38450287.

Given that,

The equation;

\dfrac{9}{n^2+1} =\dfrac{n+3}{4}

We have to find,

How many extraneous solutions does the equation?

According to the question,

An extraneous solution is a solution value of the variable in the equations, that is found by solving the given equation algebraically but it is not a solution of the given equation.

To solve the equation cross multiplication process is applied following all the steps given below.

\rm \dfrac{9}{n^2+1} =\dfrac{n+3}{4}\\\\9 (4) = (n+3) (n^2+1)\\\\36 = n(n^2+1) + 3 (n^2+1)\\\\36 = n^3+ n + 3n^2+3\\\\n^3+ n + 3n^2+3 - 36=0\\\\n^3+ 3n^2+n -33=0\\

The roots (zeros) are the  x  values where the graph intersects the x-axis. To find the roots (zeros), replace  y

with  0  and solve for  x. The graph of the equation is attached.

n  ≈  2.38450287

Hence, The equation has one extraneous solution which is n  ≈  2.38450287

For more information refer to the link.

brainly.com/question/15070282

5 0
2 years ago
Solve the equation for x<br> 3x/4+2=x/4+3
SIZIF [17.4K]

Answer:

x = 2

Step-by-step explanation:

I just chucked it into Wolfram Alpha and it showed me x = 2

also for more proof, insert positive 2 in both x's

6 0
3 years ago
Find the value of y, rounded to the nearest tenth. Please help me, I'd appreciate it!!
Blababa [14]
If a secant<span> and a </span><span>tangent of a circle </span><span>are drawn from a point outside the circle, then the product of the lengths of the secant and its external segment equals the square of the length of the tangent segment.
</span><span>
y</span>² = 7(15+7)
<span>y</span>² = 7*22
<span>y</span>² = 154
<span>y = </span>√154
<span>y = 12.4  </span>← to the nearest tenth<span>
</span><span>
</span>
8 0
2 years ago
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