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Wewaii [24]
2 years ago
8

Could someone tell me if I’m right please? WILL GIVE BRAINLIEST!

Mathematics
1 answer:
katrin2010 [14]2 years ago
5 0
Yes you are correct! because there are no values of x that make the equation true.
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(H/6 )- (1)<br> Solve for H<br> Please help me
likoan [24]

All you need to do for this is remove the parenthese and your answer will be \frac{H}{6} -1 because that's the furthest it can be simplified.

4 0
3 years ago
43. Find the image of the point (1,2) when reflected<br>by the line x=-1​
dolphi86 [110]

Answer:

-3, 2

Step-by-step explanation:

4 0
3 years ago
Hi i need help below thank you 32 POINTS
lara [203]
A = (pi) * r*2
(pi) = 3.14
r = d/2.....r = 17/2 or 8.5

A = 3.14 * 8.5^2
A = 3.14 * 72.25
A = 226.86 rounds to 226.9 m^2 <==
6 0
3 years ago
A local car dealer claims that 25% of all cars in San Francisco are blue. You take a random sample of 600 cars in San Francisco
sammy [17]

Answer:

No, we can't reject the dealer's claim with a significance level of 0.05.

Step-by-step explanation:

We are given that a local car dealer claims that 25% of all cars in San Francisco are blue.

You take a random sample of 600 cars in San Francisco and find that 141 are blue.

<u><em>Let p = proportion of all cars in San Francisco who are blue</em></u>

SO, Null Hypothesis, H_0 : p = 25%   {means that 25% of all cars in San Francisco are blue}

Alternate Hypothesis, H_A : p \neq 25%   {means that % of all cars in San Francisco who are blue is different from 25%}

The test statistics that will be used here is <u>One-sample z proportion</u> <u>statistics</u>;

                                  T.S.  = \frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }  ~ N(0,1)

where, \hat p = sample proportion of 600 cars in San Francisco who are blue =   \frac{141}{600} = 0.235

            n = sample of cars = 600

So, <u><em>test statistics</em></u>  =  \frac{0.235-0.25}{{\sqrt{\frac{0.235(1-0.235)}{600} } } } }

                               =  -0.866

<em>Now at 0.05 significance level, the z table gives critical values of -1.96 and 1.96 for two-tailed test. Since our test statistics lies within the range of critical values of z so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.</em>

Therefore, we conclude that 25% of all cars in San Francisco are blue which means the dealer's claim was correct.

4 0
3 years ago
mr. and Mrs . Coronado took a bus to belmopan . they left at 7:15 a.m. and arrived at 8:00 a.m . How long was the trip show ur w
m_a_m_a [10]

Answer:

The trip was 45 minutes

Step-by-step explanation:

you take 60 minutes which is an hour and subtract 15 to get 45 minutes

6 0
3 years ago
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