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KonstantinChe [14]
3 years ago
15

PLEASE HELP Determine W and X in Circle M

Mathematics
1 answer:
e-lub [12.9K]3 years ago
8 0

your answer will be

w=<u>16°</u>

X=<u>148°</u>

Step-by-step explanation:

hope it helps you

have a great day!!

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Simplify the ratio 24:120
Vaselesa [24]
24: 1, 2, 3, 4, 6, 8, 12, 24
120: 1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 20, 24, 30, 40, 60, 120

The GCF of 24 and 120 is 24.

24:120 / 24:24 = \\  1:5
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3 years ago
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PLEASE HELP ME:<br><br> Find the perimeter of the figure. Round to the nearest tenth.
Ksenya-84 [330]

Answer:

perimeter = 20.9 units

Step-by-step explanation:

perimeter

perimeter = distance around two dimensional shape

= addition of all sides lengths

<h2>perimeter of the figure</h2><h2>= AB+BC+CD+AD</h2>

distance formula:

d =  \sqrt{(  x_{2} -  x_{1})  {}^{2}   + ( y_{2} -  y_{1}) {}^{2}  }

<h3>1) distance of AB</h3>

A(-3,0) B(2,4)

x1 = -3 x2 = 2

y1 = 0 y2 = 4

(substitute the values into the distance formula)

ab =  \sqrt{(2 - ( - 3)) {}^{2}  + (4 - 0) {}^{2} }

ab =  \sqrt{5 {}^{2} + 4 {}^{2}  }

ab =  \sqrt{41}AB = 6.4 units

<h3>2) distance of BC</h3>

B(2,4) C(3,1)

x1 = 2 x2 = 3

y1 = 4 y2 = 1

bc =  \sqrt{(3 - 2) {}^{2}  + (1 - 4) {}^{2} }

bc = \sqrt{1 {}^{2} + ( - 3) {}^{2}  }

bc =  \sqrt{10}

BC = 3.2 units

<h3>3) distance of CD</h3>

C(3,1) D(-4,-3)

x1 = 3 x2 = -4

y1 = 1 y2 = -3

cd =  \sqrt{( - 4 - 3) {}^{2}  + ( - 3 - 1)) {}^{2} }

cd =  \sqrt{( -   7) {}^{2}  + ( - 4 ){}^{2} }

cd =   \sqrt{65}

CD = 8.1 units

<h3>4) distance of AD</h3>

A(-3,0) D(-4,-3)

x1 = -3 x2 = -4

y1 = 0 y2 = -3

ad =  \sqrt{(  - 4 - ( - 3)) {}^{2}  +  ( - 3 - 0) {}^{2} }

ad =  \sqrt{( - 1) {}^{2} + ( - 3) {}^{2}  }

ad =  \sqrt{10}

AD = 3.2 units

<h2>perimeter of figure</h2>

= AB+BC+CD+AD

= 6.4 + 3.2 + 8.1 + 3.2

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3 years ago
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oksano4ka [1.4K]

Answer:

x = 3

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Answer:

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Step-by-step explanation:

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lana66690 [7]

We need to convert this equation to slope-intercept form first.

We can do that by solving for y.

x - 5y = 15

<em><u>Add 5y to both sides.</u></em>

x = 5y + 15

<em><u>Subtract 15 from both sides.</u></em>

x - 15 = 5y

<em><u>Divide both sides by 5.</u></em>

y = 1/5x - 3

We now know the slope is 1/5.

The slope of the line perpendicular to the line with a slope of 1/5 is -5.

The slope of a perpendicular line is the negative reciprocal of the original slope.

Using a graphing calculator, we know the y-intercept of the line that is perpendicular to the original line must have a y-intercept of -6 to run through the points (-2, 5).

The equation of the new line is y = -5x - 6.


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3 years ago
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