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KonstantinChe [14]
3 years ago
15

PLEASE HELP Determine W and X in Circle M

Mathematics
1 answer:
e-lub [12.9K]3 years ago
8 0

your answer will be

w=<u>16°</u>

X=<u>148°</u>

Step-by-step explanation:

hope it helps you

have a great day!!

You might be interested in
3/8+1/8 4/5+3/4 6/7+2/5 Rewrite each expression as a single fraction
Karo-lina-s [1.5K]

3/8+1/8=4/8=1/2 simplified

4/5+3/4= common denominator of 20

new fraction: 16/20+15/20

31/20=1 11/20 simplified

6/7+2/5 common denominator of 35

new fraction: 30/35+14/35

44/35

1 9/35 simplified


6 0
4 years ago
What's the absolute value of |10-34|
My name is Ann [436]

Answer:

24

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

  • |Absolute Value| - makes any negative number positive

Step-by-step explanation:

<u>Step 1: Define</u>

|10 - 34|

<u>Step 2: Evaluate</u>

  1. Subtract:                    |-24|
  2. |Absolute|:                  24
5 0
3 years ago
The legs of a right triangle measure 5√2 cm and 4√2 cm. Find the area.
lianna [129]
The area of right triangle=1/2*leg1*leg2=20 cm2
4 0
3 years ago
Read 2 more answers
Find the value of y when x=3<br> y=2x3<br> y=0
MaRussiya [10]
Answer: 54

Why? You need to put 3 in for x so you get
2(3)^3
3 to the third power is 3*3*3 which equals 27
2(27)
Now you must do 2 times 27 and you get 54

Hope this helps
8 0
4 years ago
Burning coal yields about 30 x 106 joules of energy per kilogram of coal burned, but only 30% of that energy goed into electrici
abruzzese [7]

Answer:

Number of bulbs which can be lit using 1 kg of coal = 9

Step-by-step explanation:

Energy yielded by burning 1 kg of coal = 30 × 106 joules

                                                                = 3180 joules

Amount of energy that can be used for electricity = 30 % of 3180 joules

                                                                                   = 0.30 × 3180

                                                                                    = 954 joules

Energy needed for lighting one bulb = Wattage of bulb × No. of hours of lighting

⇒ Energy needed for lighting one bulb = 100 × 1

                                                                  = 100 joules

\text{Now, Number of bulbs which can be lit for one hour = }\frac{954}{100}\\\\\implies\bf\textbf{Number of bulbs = }9.54\approx 9

Hence, Number of bulbs which can be lit using 1 kg of coal = 9

4 0
4 years ago
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