Perpendicular line always have slopes that are negative reciprocals of one another. Mathematically,
m1*m2=-1
So to be perpendicular to the line given, let's rearrange it to the point slope form of a line...
3y=6x ?3 (not sure what you wanted to type there)
anyway isolating y by dividing both side by three will leave 2x where 2 is the slope.
So for the other line to be perpendicular, m*2=-1, m=-1/2, now we have:
y=-x/2 +b, we can now you the point given to solve for b
4=-2/2 +b
4=-1+b
b=5 so
y=-x/2 +5 or more neatly
y=(10-x)/2
The answer is C since the 1 in the square root is a horizontal shift to the left by one and a vertical shift up by 7
Answer:
25π units^2
Step-by-step explanation:
The shape is a quarter circle with radius 10 units.
area of circle = πr^2
area of a quarter circle = (1/4)π(10 units)^2
area = 25π units^2
Answer:
The answer is B
Step-by-step explanation:
Answer:
m 1 = 45 degrees because 1 and the angle measuring 135 degrees are supplementary angles.
m 2 = 95 degrees because 2 and the angle measuring 95 degrees are vertical angles.
m 3 = 40 degrees because 1, 2, and 3 form a triangle
Step-by-step explanation:
