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igor_vitrenko [27]
3 years ago
14

Enter the missing exponent. 9/49 = ( 3/7 )^

Mathematics
1 answer:
Deffense [45]3 years ago
7 0
The missing exponent is 2
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QF Q6.) Find the function for a.
irakobra [83]
The function for a is (f o g) (x) = 8x^2-10.



Explanation

=========================
f(x)=2x-4, g(x)=4x^2-3, (f o g)=f(g(x))  

I already knew that the g of x is equal to 4x^2-3 so I substitute inside of the g of x

g(x)=4x^2-3 =======> f(x)=4x^2-3 =============> 2(4x^2-3)-4 

simplify it 
 
2(4x^2-3)-4  =======> 8x^2-6-4 =========> 8x^2-10

(f o g) = 8x^2-10


5 0
3 years ago
Read 2 more answers
PLZZzzzzz Help me ASAP!!!
ziro4ka [17]

Answer:

The estimate is 217.5.

8 0
3 years ago
Read 2 more answers
a company decided to increase the size of the box for the packaging of their alcohol products. the length of the original packag
Igoryamba

Answer:

The answer is below

Step-by-step explanation:

a company decided to increase the size of the box for the packaging of their alcohol products. the length of the original packaging box was 40 cm longer than its width and the height 12 cm, volume was at most 4800 cm3. Suppose the length of the new packaging box is still 40cm longer than its width and the height is 12cm, what mathematical statement would represent the volume of the new packaging box?​

Solution:

Let the width of the box be x cm.

The length of the box is 40 cm longer than the width, therefore the length of the box = x + 40

The height of the box = 12 cm

The volume of the box can be gotten from the formula:

Volume = length × width × height

Substituting:

Volume = (x + 40) × (x) × 12

Volume = 12x(x + 40)

Therefore the volume of the new box is 12x(x + 40)

8 0
2 years ago
#4 home do I find which one it is?
lina2011 [118]
\bf \begin{array}{lllll}
solutions&graphs&slopes\\
----&----&----\\
\textit{exactly one}&
\begin{array}{llll}
\textit{the two lines intersect}\\
\textit{at one point}
\end{array}&\textit{different slopes}\\\\
infinitely\quad many&
\begin{array}{llll}
\textit{the two lines coincide}\\
\textit{one is right on top}\\
\textit{ of the other}
\end{array}&
\begin{array}{llll}
\textit{equal slopes}\\
\textit{equal y-intercepts}
\end{array}
\end{array}

\bf \textit{no solution}\qquad\quad &\textit{lines are parallel} \qquad &
\begin{array}{llll}
\textit{equal slopes}\\
\textit{different y-intercepts}
\end{array}
\end{array}

for example, let's look at the first set

y+3x =5   or  y = -3x+ 5
and               y = -3x + 2
                    y =  m  + b

the slopes are equal, the y-intercepts differ
that means, they're just parallel lines, no solution
8 0
3 years ago
How to translate equation into a sentence j 16=35
timama [110]
J time sixteen equals thirty five.
5 0
3 years ago
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