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3 years ago

5

PLEASE HELP‼️ A B C D

1 answer:

Naily [24]3 years ago

4 0

Answer:

A

Step-by-step explanation:

go with that

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What is the length of BC? If your answer is not an integer, leave it in simplest radical form?

nexus9112 [7]

ANSWER

$|BC|=12\sqrt{2}\: ft$

EXPLANATION

The given right triangle is an isosceles triangle because

$m \: < \: B = 45 \degree = m \: < \: C$
This implies that,

$|AB|=12ft=|AC|$

From the Pythagoras Theorem,

$|BC|^2=|AB|^2+|AC|^2$

$|BC|^2= {12}^{2} + {12}^{2}$

$|BC|^2=2 \times {12}^{2}$

$|BC| = \sqrt{ {12}^{2} \times 2 }$

$|BC|=12\sqrt{2}\: ft$

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3 years ago

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When rolling a number cube 500 times, how many times can you expect to roll a 3

Montano1993 [528]

he rolling number cute of 1,500

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2 years ago

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Simplify -62 ÷ 12 - 2(-7).<br><br> -17<br> 35<br> -35<br> 11

galina1969 [7]

The answer is 53/6 in fraction form

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3 years ago

Need answer to 4 and 5

algol13

Answer:

Substitute n =1, 2, 3, 4, 5 to get the first five terms.

Step-by-step explanation:

(4). $g_n = 2 . 3^{n - 1}$

To find the first term, substitute n = 1.

Therefore, $g_1 = 2 . 3^{1 - 1} = 2 . 3^{0} = 2 . 1$ = 2

$g_2 = 2 . 3^{2 - 1} = 2 . 3$ = 6

$g_3 = 2 . 3^{3 - 1} = 2 . 3^{2} = 2 . 9$ = 18

$g_4 = 2 . 3^{4 - 1} = 2 . 3^{3} = 2 . 27$ = 54

$g_5 = 2 . 3^{5 - 1} = 2 . 3^{4} = 2 . 81$ = 168

Therefore the first five terms of the sequence are: 2, 6, 18, 54, 168.

(5). $t_n = \frac{2}{3}t_{n - 1}$

$t_2 = \frac{2}{3} t_{2 - 1} = \frac{2}{3}t_1 = \frac{2}{3}6$ = 4

$t_3 = \frac{2}{3} t_2 = \frac{2}{3}. 4 = \frac{8}{3}$

$t_4 = \frac{2}{3}t_3 = \frac{2}{3}\frac{8}{3} = \frac{16}{9}$

$t_5 = \frac{2}{3}t_4 = \frac{2}{3}\frac{16}{9} = \frac{32}{27}$

Therefore the first five terms in the sequence are: 6, 4, 8/3, 16/9, 32/27.

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3 years ago

How is dividing 140 by 20 the same as dividing 1,400 by 200?

Goryan [66]

It's the same only adding a zero at the end

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