2 negative three.....use Math-way
9514 1404 393
Answer:
- x ≤ 4
- x > 10
- x ≤ -7
Step-by-step explanation:
We're guessing you want to solve for x in each case. You do this in basically the same way you would solve an equation.
1. 3x +2 ≤ 14
3x ≤ 12 . . . . . subtract 2
x ≤ 4 . . . . . . . divide by 3
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2. -5 +2x > 15
2x > 20 . . . . . . add 5
x > 10 . . . . . . . . divide by 2
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3. -2x +4 ≥ 18
4 ≥ 18 +2x . . . . . add 2x
-14 ≥ 2x . . . . . . . subtract 18
-7 ≥ x . . . . . . . . . divide by 2
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<em>Additional comment</em>
The statement above that the same methods for solving apply to both equations and inequalities has an exception. The exception is that some operations reverse the order of numbers, so make the inequality symbol reverse. The usual operations we're concerned with are <em>multiplication and division by a negative number</em>: -2 < -1; 2 > 1, for example. There are other such operations, but they tend to be used more rarely for inequalities.
You will note that we avoided division by -2 in the solution of the third inequality by adding 2x to both sides, effectively giving the variable term a positive coefficient. You will notice that also changes its relation to the inequality symbol, just as if we had left the term where it was and reversed the symbol: -2x ≥ 14 ⇔ -14 ≥ 2x ⇔ x ≤ -7 ⇔ -7 ≥ x
Answer:
Step-by-step explanation:
y=12x−2. parallel lines have the same slope 12
find b at point (3,-2)
y=12x+b
-2=12(3)+b
-2-36=b
b=-36
the equation has to be y=12x-38
when you input the point(3,-2)
-2=12(3)-38
-2=-2 correct
To determine the number of modules that is in each story, we simply divide the number of modules by the number of stories.
= 140 / 14
Simplifying,
= 10 modules / story
Therefore, by even distribution we note that there are 10 modules per story.
Distance from J to F = b
D from F to K = a
a^2+b^2=JK^2
D from K to G = a
D from G to L = b
a^2+b^2=KL^2
D from L to H = b
D from H to M = a
a^2+b^2=LM^2
D from M to E = a
D from E to J = b
a^2+b^2=MJ^2
For each side, I used the Pythagorean theorem (a^2+b^2=c^2) to find the length. Since every side of the quadrilateral squared (aka to the power of two) equals a^2+b^2, every side squared equals each other. So JK^2=KL^2=LM^2=MJ^2. If you take the square root of each side of the equal signs, you’re left with JK=KL=LM=MJ. In order for a quadrilateral to be a rhombus, each side must be equivalent. Each side in this quadrilateral is equivalent, therefore it is a rhombus.
