4 and 1
3 and 2
im pretty sure thats is the answer, the question is quite vague.
Answer: −(b+4)(2b−3)
Step-by-step explanation:
1. Factor out the negative sign.
−(2b^2+5b−12)
2. Split the second term in 2b^2+5b−12 into two terms.
−(2b^2+8b−3b−12)
3.Factor out common terms in the first two terms, then in the last two terms.
−(2b(b+4)−3(b+4))
4. Factor out the common term b+4b+4b+4.
−(b+4)(2b−3)
10.2 x 2 = 20.40
9.4 x 3 = 28.20
Total= 48.60
If there are only two colors (let's say blue and red), here's what can happen:
sock #1 is blue
#2 is either blue or red. If blue, it matches #1 and you have a pair.
if red, go to #3
#3-either blue or red. If blue, matches #1. If red, matches #2.
OR sock #1 is red... then just reverse the colors. Basically, if you have three things that can only be in two groups, then even if two of them are different, the last one has to match one of them.
Answer:
46
Step-by-step explanation:
