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valentinak56 [21]
3 years ago
9

If p varies jointly as q and r, and p = 150 when q = 18 and r = 5, find q when p = 345 and r = 9. TA​

Mathematics
1 answer:
hichkok12 [17]3 years ago
8 0

Answer:

the answer is saltiness, why?

Step-by-step explanation:

because when i was little my bro used to ask me to go up and down with my mouth on his cucumber and i hated it but he offered me candy. Anyway now he gives me 5$ so ill do it more and as many times :D so i can get a new robucks card

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A company sells boxes of duck calls (d) for $35 and boxes of turkey calls (t) for $45. they make batches of duck calls that fill
SIZIF [17.4K]

Answer:

Option A is the correct choice.

Step-by-step explanation:

Let d be the number of boxes of duck calls and t be the number of boxes of turkey calls.

We have been given that a company sells boxes of duck calls for $35 and boxes of turkey calls (t) for $45, so the revenue earned from selling d boxes of duck and t boxes of turkey call will be 35d and 45t respectively.

Further, the company plan to make $300. We can represent this information as:

35d+45t=300...(1)

We are also told that they make batches of duck calls that fill 6 boxes and batches of turkey calls that fill 8 boxes. the company only has 42 boxes. We can represent this information as:

6d+8t=42...(2)

6d=42-8t...(2)

Therefore, our desired system of equation will be:

35d+45t=300...(1)

6d=42-8t...(2)  


8 0
3 years ago
Can someone help 30 points!
irina1246 [14]
We cannot solve for a numerical value of p, but rather set the equation equal to p.

w = 4/(p+2)

(Multiply both sides by the denominator)

w(p+2) = 4

(divide both sides by w)

p+2 = 4/w

(Subtract 2 from both sides) (also 2/1)

p = (4-2)/w

p = 2/w
3 0
3 years ago
A distribution x is known to have a mean value of 5 and a standard deviation of 5. what is its mean square value (i.e., the expe
telo118 [61]
\mathbb V(X)=\mathbb E(X^2)-\mathbb E(X)^2
\implies 5^2=\mathbb E(X^2)-5^2
\implies\mathbb E(X^2)=50
8 0
3 years ago
QS¯¯¯¯¯¯¯ bisects ∠PQR . If m∠PQS = 5x and m∠RQS = 2x + 6, then what is m∠PQR ? m∠PQR is
soldi70 [24.7K]

Answer:

PQR = 20

Step-by-step explanation:

Given

Bisector: QS

PQS = 5x

RQS = 2x + 6

Required

Determine PQR

Since PQR is bisected to PQS and RQS, we have that

PQS = RQS

Substitute expressions for PQS and RQS

5x = 2x + 6

Collect Like Terms

5x - 2x = 6

3x = 6

Divide both sides by 3

x = 2

Solving for PQR;

PQR = PQS + RQS

PQR = 5x + 2x + 6

PQR = 7x + 6

Substitute 2 for x

PQR = 7 * 2 + 6

PQR = 14 + 6

PQR = 20

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