Answer:
oneMore(oneMore(oneMore(oneMore(oneMore(0)))))
Explanation:
- As a function has been explained which when given an integer results as a next integer. oneMore(given-integer)= next integer
- As we are restricted to use 0 only and can't use operators like + - * /.
- We have to obtain a value 5
- So doing step-by-step:
(oneMore(0))=1
(oneMore(oneMore(0)))=2
(oneMore(oneMore(oneMore(0))))=3
(oneMore(oneMore(oneMore(oneMore(0)))))=4
oneMore(oneMore(oneMore(oneMore(oneMore(0)))))=5
Answer:
Its D DLSR and Mirrorless
Explanation:
Tell me if you get it wrong or right :3
Answer:
see explaination
Explanation:
function [] =
inverse(A,B)
da = det(A);
disp("The det of A is");
disp(da);
inva = inv(A);
disp("The inverse of A is");
disp(inva);
x = inva*B;
disp("The value of X is");
disp(x);
rk = rank(A);
disp("The rank of X is");
disp(rk);
Di = eig(A);
disp("The eigen values of A is");
disp(Di);
[V,Di] = eig(A);
disp("The eigen vectors of A are (Each column represents one column vector)");
disp(V);
end
A = [1,2;4,5];
B = [1,2;4,5];
inverse(A,B);
%ab = [num2str(t)," ",num2str(dx)," ",num2str(dy)];
%disp(ab);
Answer:
The "A" option is correct.
Explanation:
For CSS flexbox layout, the property "align-content" requires that the space in the flexbox is more than enough to show the items. In this case, to distribute evenly the items and show the first and last items aligned with the start and end of the main axis, the only suitable option is "space-between". This option leaves no space at the start or at the end of the flexbox, distributing the remaining space between the elements into the flexbox.
Answer:
The correct answer to the following question will be "Θ(n2)
". The further explanation is given below.
Explanation:
If we're to show all the objects that exist from either the first as well as the second vector, though not all of them, so we'll have to cycle around the first vector, so we'll have to match all the objects with the second one.
So,
This one takes:
=
And then the same manner compared again first with the second one, this takes.
=
Therefore the total complexity,
= Θ(n2)