-(5 + (-11.3)) + (-4.3)
-(5 - 11.3) + (-4.3)
Distribute -1 into the parenthesis:
-5 + 11.3 + (-4.3)
-5 + 11.3 - 4.3
Add:
6.3 - 4.3
Subtract:
2
I am guessing is he lit all candles and umm maybe he lit something else on fire and he still has fire on the thing he lit everything with. This is kinda confusing. Good luck lol.
Answer:c
Step-by-step explanation:
Decide the numbers
Answer:
Step-by-step explanation:
Assume that f(x) = 0 for x outside the interval [4,9]. We will use the following
![Var(X) = E[X^2}- (E[X])^2](https://tex.z-dn.net/?f=Var%28X%29%20%3D%20E%5BX%5E2%7D-%20%28E%5BX%5D%29%5E2)
Standard deviation = ![\sqrt[]{Var(X)}](https://tex.z-dn.net/?f=%20%5Csqrt%5B%5D%7BVar%28X%29%7D)
Mean =
Then,
![E[X] = \int_{4}^{9}\frac{1}{5}dx = \frac{9^2-4^2}{2\cdot 5} = \frac{13}{2}](https://tex.z-dn.net/?f=E%5BX%5D%20%3D%20%5Cint_%7B4%7D%5E%7B9%7D%5Cfrac%7B1%7D%7B5%7Ddx%20%3D%20%5Cfrac%7B9%5E2-4%5E2%7D%7B2%5Ccdot%205%7D%20%3D%20%5Cfrac%7B13%7D%7B2%7D)
![E[X^2] = \int_{4}^{9}\frac{x^2}{5}dx = \frac{9^3-4^3}{3\cdot 5} = \frac{133}{3}](https://tex.z-dn.net/?f=E%5BX%5E2%5D%20%3D%20%5Cint_%7B4%7D%5E%7B9%7D%5Cfrac%7Bx%5E2%7D%7B5%7Ddx%20%3D%20%5Cfrac%7B9%5E3-4%5E3%7D%7B3%5Ccdot%205%7D%20%3D%20%5Cfrac%7B133%7D%7B3%7D)
Then, 
Then the standard deviation is ![\frac{5}{2\sqrt[]{3}}](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B2%5Csqrt%5B%5D%7B3%7D%7D)