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user100 [1]
3 years ago
7

None aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa

Mathematics
1 answer:
Yakvenalex [24]3 years ago
7 0

Answer:

what

Step-by-step explanation:

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Pls help with this !!
photoshop1234 [79]

Answer:

25.12 so the nearest 10 is 25.10

5 0
3 years ago
a local community college has 860 students. Of these 860 students, 220 ride bicycles. Write the number of bike riders as a fract
Zinaida [17]

Answer:

11/43

Step-by-step explanation:

A local community college has 860 students

Out of this 860 students, 220students ride bikes

Therefore the fraction of bike riders to the number of students can be calculated as follows

= 220/860

= 11/43

4 0
2 years ago
Fill in the blank to make the expression a perfect square:
tigry1 [53]

Answer:

64

Step-by-step explanation:

So here you're just completing the square. the equation you gave is simply: n^2+16n+c where c is the unknown value we're solving for. Whenever you complete the square, you add (b/2)^2

The reason for this, is because whenever you write a binomial as a perfect square it's in the form: (x+b)^2 and this binomial expands out to become: x^2+2bx+b^2

If we write the second term of the binomial as b/2 we get:

(x+\frac{b}{2})^2=x^2+2(\frac{b}{2})x+(\frac{b}{2})^2

which simplifies to:

(x+\frac{b}{2})^2=x^2+bx+(\frac{b}{2})^2

and as you can see the last term is (b/2)^2, which is why we need to add that part for it to be a perfect square.

So we would need to add (16/2)^2 = 8^2 = 64

This way, we can express it as a perfect square binomial: (n+8)^2 which expands out to: n^2+2(8)(n)+8^2 = n^2+16n+64

7 0
1 year ago
X^2-4x-11=0 completing the square
yawa3891 [41]
<span>The answers are either:

x=<span>2+<span><span><span>√15</span><span> or </span></span>x</span></span></span>=<span>2−<span>√<span>15

Hope this helps!
</span></span></span>
5 0
3 years ago
Read 2 more answers
show three ways to estimate 3/5 ×9 1/2. identify each method you use. ( I have estimating and compatible. another one is what I
Iteru [2.4K]
12 because I said so :)
6 0
3 years ago
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