0.1125 kg
Step-by-step explanation:
Step 1:
Let us assume that 48 inches of coil of steel weighs 10.800 kg.
We have to find the weight of 0.5 inch coil.
Step 2:
In this problem we assume that it is given in direct relationship.
Therefore, Problem becomes
48 inches weigh 10.8 kg
0.5 inches weigh X kg
(48 / 0.5) = ( 10.8 / X)
X = (10.8 × 0.5) / 48
X = 0.1125 kg
Answer:
842.04 cm³
Step-by-step explanation:
Cylinder:
diameter = 6 cm
r = 6/2 = 3cm
h = 4 cm
Volume of cylinder = πr²h
= 3.14 * 3 * 3 * 4
= 113.04 cm³
Cube:
side = 9 cm
Volume of cube = side * side *side
= 9*9*9
= 729 cm³
Volume 0f composite figure = volume of cylinder + volume of cube
= 113.04 + 729
= 842.04 cm³
Leg CB = x and leg DE = y - 1. Becuase of the markings on the triangles, we know that CB = DE; therefore, x = y - 1. So let's use that x value when we set the 2 hypotenuses equal to each other. Before any substition, 3x - 2 = 2y + 1. Subbing in for x we have 3(y - 1) - 2 = 2y + 1. And 3y - 3 - 2 = 2y + 1. Combining like terms we have y = 6. If y = 6, we will sub it into the leg equation to find x. x = y - 1; therefore, x = 6 - 1 and x = 5. There you go! x = 5 and y = 6
if im mistaken your answer is a. it makes the most sense to me
