Which equation represents a line parallel to the x-axis? Y = x X= 4 Y = 4 Y= x + 4
1 answer:
You might be interested in
Answer:
{-1, 1/2, 2/3, 1}
Step-by-step explanation:
I find a graphing calculator to be a most useful tool for problems like this. (See attached.)
_____
First of all, observe that the constant is -2, so 0 is not a zero.
It is often useful to look at the sum of coefficients. Here, that is 0, indicating 1 is a zero.
You can divide that out, or simply continue by looking at the sum of coefficients with odd-degree terms negated. Then you have 6 +7 -4 -7 -2 = 0, indicating -1 is also a zero.
__
At this point, it can be useful to divide out the factors you know. The synthetic division tableaus attached show that work. First is division by (x+1), then by (x -1).
The result of doing that is the quadratic ...
6x^2 -7x +2 = 0
This can be factored ...
(6x^2 -3x) -(4x -2) = 0 . . . . . . rewrite -7x and group term pairs
3x(2x -1) -2(2x -1) = 0 . . . . . . . factor each pair
(3x -2)(2x -1) = 0 . . . . . . the factorization of the remaining quadratic
The zeros of this are the values of x that make the factors zero: 2/3 and 1/2.
The zeros of the given function f(x) are x ∈ {-1, 1/2, 2/3, 1}.
Answer:
The integral diverges
Step-by-step explanation:
Consider the integral from 0 to infinity of
We can do this in parts
When we substitute limits infinity we find that the values become infinity
Hence the integral diverges
The given improper integral diverges
3.122
The process to getting this comes in many steps. Firstly, you need to find the angles for JLK and MLJ. To find JLK use the arcsin function using the opposite side and the hypotenuse.
Arcsin(Opp/Hype) = JLK
Arcsin(.5) = JLK
30 degrees = JLK
This means MLJ = 31 degrees since they add up to 61 degrees.
Now we need to find the length of LJ, which we can do using the Pythagorean Theorem.
3^2 + JL^2 = 6^2
9 + JL^2 = 36
JL^2 = 27
JL =
Now that we have the angle of MLJ and the length of JL, we can use the tangent function to find MJ.
Tan(angle) = opp/adj
Tan(31) = MJ/
Tan(31) = MJ
3.122 = MJ
The process to getting this comes in many steps. Firstly, you need to find the angles for JLK and MLJ. To find JLK use the arcsin function using the opposite side and the hypotenuse.
Arcsin(Opp/Hype) = JLK
Arcsin(.5) = JLK
30 degrees = JLK
This means MLJ = 31 degrees since they add up to 61 degrees.
Now we need to find the length of LJ, which we can do using the Pythagorean Theorem.
3^2 + JL^2 = 6^2
9 + JL^2 = 36
JL^2 = 27
JL =
Now that we have the angle of MLJ and the length of JL, we can use the tangent function to find MJ.
Tan(angle) = opp/adj
Tan(31) = MJ/
3.122 = MJ