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3 years ago

Which equation represents a line parallel to the x-axis? Y = x X= 4 Y = 4 Y= x + 4

Mathematics

1 answer:

maks197457 [2]3 years ago

3 0

Y=x+4 it’s a equation that represents a line parallel

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How do i find the LCD? ( Lowest Common Denominator )

Jet001 [13]

Answer:

First for example let's say

your going to doing what you do normally for gcf but then make an l and times it if that makes sense

Step-by-step explanation:

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3 years ago

Read 2 more answers

Find the area of a swimming pool that is 23.15ft. long and 123ft wide. Show your work

Mariana [72]

Answer:

The area of the swimming pool is 2,847.45ft, assuming this pool is a rectangle.

Step-by-step explanation:

A=l*w

A=23.15*123

A=2847.45ft

8 0

4 years ago

Find the simple interest and amount when principal = Rs. 6000, rate = 6% per annum and time = 4 years

Alinara [238K]

Given:

Principal = Rs. 6000

Rate of simple interest = 6% per annum.

Time = 4 years

To find:

The simple interest and amount.

Solution:

Formula for simple interest:

$I=\dfrac{P\times r\times t}{100}$

Where, P is principal, r is the rate of interest and t is the number of years.

Putting P=6000, r=6 and t=4, we get

$I=\dfrac{6000\times 6\times 4}{100}$

$I=60\times 6\times 4$

$I=1440$

Now,

$Amount=Principal+Interest$

$Amount=6000+1440$

$Amount=7440$

Therefore, the simple interest is Rs. 7440 and the amount is Rs 7440.

7 0

3 years ago

A 3,000 piece of direct mailing cost 1,435. Printing cost is $550, about 31/2 times the cost of typesetting. How much did the ty

yanalaym [24]

Answer:

The typesseting cost $ 35.48.

Step-by-step explanation:

Given that a 3,000 piece of direct mailing cost $ 1,435, and printing cost is $ 550, about 31/2 times the cost of typesetting, to determine how much did the typesetting cost the following calculation must be performed:

31/2 = 15.5

550 / 15.5 = X

35.48 = X

35.48 x 15.5 = 550

Thus, the typesseting cost $ 35.48.

3 0

3 years ago

Motorola used the normal distribution to determine the probability of defects and the number of defects expected in a production

Lena [83]

The question supplied is incomplete :

The x parameters aren't given ; "Units with weights less than or greater than ounces will be classified as defects"

Assume the unit weights Given are ;

Units with weights less than 10.8 or greater than 11.2 ounces will be classified as defects

Just follow the procedure in the solution for any value of unit weight interval given.

Answer:

0.3173

Step-by-step explanation:

Mean weight, m = 11 ounces

Standard deviation, s = 0.2 ounces

Find the Zscore for each unit weight :

Z = (x - mean) / standard deviation

P(x < 10.8) :

Z = (10.8 - 11) / 0.2 = - 1

P(Z < - 1) = 0.15866

P(x > 11.2) :

Z = (11.2 - 11) / 0.2 = 1

P(Z > 1) = 0.84134

P(x < 11.2) - P(x < 10.8) = 1 - (P(Z < 1) - P(Z < - 1)) = 1 - 1 - (0.84134 - 0.15866) = 1 - 0.68268 = 0.31732

Hence, Probability of a defect is 0.3173

7 0

3 years ago