Step-by-step explanation:
what the f♤ck are those. any teachers give u it tell them to go do it
Answer:
B, C, E
Step-by-step explanation:
Elena’s aunt pays her $1 for each call she makes to let people know about her aunt’s new business. The table shows how much money Diego receives for washing windows for his neighbors.
Select all the statements about the situation that are true.
A. Elena makes more money for making 10 calls than Diego makes for washing 10 windows.
Elena:
$1 = 1 call
$10 = 10 calls
Diego:
27 windows = $30
10 windows = $x
Cross product
27*x = 30*10
27x = 300
x = 300/27
x = $11.11
Statement A not true
B. Diego makes more money for washing each window than Elena makes for making each call.
Diego:
10 windows = $11.11
Each window = $11.11/10
= $1.11
Statement B is true
C. Elena makes the same amount of money for 20 calls as Diego makes for 18 windows
Elena:
20 calls = $20
Diego:
18 windows = 18 × $1.11
= $19.98
Approximately $20 to the nearest whole dollar
Statement C is true
D. Diego needs to wash 35 windows to make as much money as Elena makes for 40 calls.
Diego
35 × $1.11 = $38.85
Approximately $39
Elena:
40 calls = $40
Statement D is not true
E. The equation y = x, where y is the number of dollars and x is the number of calls, represents Elena’s situation.
Statement E is true
Answer:
r = 8,9,10
Step-by-step explanation:
The given inequality is :
5r≤6r−8 ...(1)
We need to find the value of r.
Subtracting 5r to both sides of the inequality .
5r-5r≤6r-5r−8
0≤r−8
r ≥ 8
Hence, the values of r are 8,9,10.
Answer:
√(2 + √3)/4
Step-by-step explanation:
Sine 5π/12 = Sine (5π/6)/2
Recall
π = 180°
Thus,
Sine (5π/6)/2 = Sine (5×180 /6)/2
= Sine 150/2
Recall
Sine θ/2 = √(1 – Cos θ)/2
Thus,
Sine 150/2 = √(1 – Cos 150)/2
But, Cosine is negative in the 2nd quadrant. Thus,
Cos 150 = – Cos 30 = –√3/2
Thus,
√(1 – Cos 150)/2 = √(1 – –√3/2 )/2
= √(1 + √3/2 )/2
= √[(2 + √3)/2 ÷ 2]
= √[(2 + √3)/2 × 1/2]
= √(2 + √3)/4
Therefore,
Sine 5π/12 = √(2 + √3)/4
![\bf \cfrac{x}{4x+x^2}\implies \cfrac{\begin{matrix} x \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}}{\begin{matrix} x \\[-0.7em]\cline{1-1}\\[-5pt]\end{matrix}~~(4+x)}\implies \cfrac{1}{4+x}\qquad \{x|x\in \mathbb{R}, x\ne -4\}](https://tex.z-dn.net/?f=%5Cbf%20%5Ccfrac%7Bx%7D%7B4x%2Bx%5E2%7D%5Cimplies%20%5Ccfrac%7B%5Cbegin%7Bmatrix%7D%20x%20%5C%5C%5B-0.7em%5D%5Ccline%7B1-1%7D%5C%5C%5B-5pt%5D%5Cend%7Bmatrix%7D%7D%7B%5Cbegin%7Bmatrix%7D%20x%20%5C%5C%5B-0.7em%5D%5Ccline%7B1-1%7D%5C%5C%5B-5pt%5D%5Cend%7Bmatrix%7D~~%284%2Bx%29%7D%5Cimplies%20%5Ccfrac%7B1%7D%7B4%2Bx%7D%5Cqquad%20%5C%7Bx%7Cx%5Cin%20%5Cmathbb%7BR%7D%2C%20x%5Cne%20-4%5C%7D)
if you're wondering about the restriction of x ≠ -4, is due to that would make the fraction with a denominator of 0 and thus undefined.