<span>Hexagon DEFGHI is translated on the coordinate plane below to create hexagon D'E'F'G'H'I'
</span> the translation of hexagon DEFGHI to hexagon D'E'F'G'H'I' is<span> represents by the rule
</span><span> d. (x, y)→(x + 7, y − 7)
I ---> </span>(-8, 4)→(x + 7, y − 7)
I' →(-8 + 7, 4 − 7) = (-1,-3)
We need to notice that SSSS does not exist as a method to prove that parallelograms are congruent
Counterexample
As we can see we have the same measure of the side of the intern angles of the figures are different therefore we can't use SSSS to prove congruence
Answer:
No complex roots; 3 real roots
Step-by-step explanation:
If a third order polynomial has any complex roots, then as a rule it has 1 real root and 2 complex roots. In this particular case, the polynomial has three real roots, as can be determined by graphing the function. The graph crosses the x-axis in 3 places.
<h3>
Answer: A) high</h3>
Explanation:
Each set spans from 3 to 7 as the min and max. Since we're dealing with the same endpoints, we have perfect overlap.
8/12 and 4/6 and10/15 and20/30 and 40/60