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3 years ago

what is the equation of a line that passes through the point (1,3) and is parallel to a line with a slope of -2?

Mathematics

1 answer:

natta225 [31]3 years ago

3 0

Answer:

Step-by-step explanation:

y - 3 = -2(x - 1)

y - 3 = -2x + 2

y = -2x + 5

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Please help, I think C and D are correct, but there is only one correct answer. See attatched question.

Lelechka [254]

I'm pretty sure it's C. It seemed confusing at first to me, too. Good luck on your test!

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3 years ago

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PLSS HELP IF YOU TURLY KNOW THISS

victus00 [196]

Answer:

x=3

Step-by-step explanation:

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2 years ago

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Giải pt lượng giác sau<br> Cos x = -√3/2

Marat540 [252]

Answer:

Step-by-step explanation:

Solution for cosx=-3/2 equation:

cos((3*pi)/5)*cos((3*pi)/20) = 0

(60*x^3)/(60*x^5) = 0

cos((3*pi)/5)*cos((3*pi)/20) = 0

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1.5/100 = 0

6 0

3 years ago

∠DEF and ∠FEG are supplementary. m∠DEF=(3x+5)°, and m∠FEG=(2x)°. What is the measure of ∠DEF?

Alex787 [66]

Answer:

DEF = 110

Step-by-step explanation:

Supplementary angles add to 180

3x+5 +2x = 180

Combine like terms

5x +5 = 180

Subtract 5 from each side

5x = 175

Divide each side by 5

5x/5 = 175/5

x =35

DEF = 3x+5

= 3*35 +5

= 105+5

= 110

6 0

3 years ago

Ms. Wilson invested $34000 in two accounts, one yielding 8% interest and the other yielding 9%. If she received a total of

Digiron [165]

Answer:

Amount invested at 8 % rate = x = $ 15000

Amount invested at 9 % rate = 34000 - x = 34000 - 15000 = $ 19000

Step-by-step explanation:

Total Amount = $ 34000

Let amount invested at 8 % rate = x

Amount invested at 9 % rate = $ 34000 - x

Total interest = $ 2910

$2910 = \frac{x (8) (1)}{100} + \frac{(34000-x) (9) (1)}{100}$

291000 = 8 x + 306000 - 9 x

x = 306000 - 291000

x = 15000

So amount invested at 8 % rate = x = $ 15000

Amount invested at 9 % rate = 34000 - x = 34000 - 15000 = $ 19000

3 0

3 years ago