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Law Incorporation [45]
3 years ago
15

Olivia has budgeted 40% of her savings for a new phone. If she had $500 in her savings account, how much can she spend on the ph

one?
Mathematics
1 answer:
rodikova [14]3 years ago
4 0

Answer:200$

Step-by-step explanation:

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Brilliant_brown [7]
Multiply 3x by -6, it gives you -18 so I'm going to say D
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3 years ago
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What is the area of the circle?
hodyreva [135]

Diameter = radius x 2

So, the radius is half of the denominator.

10 / 2 = 5

A = pi x r^2

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Hope this helps!

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3 years ago
Halle solved 664/48 below. She got a quotient of 13 with a remainder of 40. How could she solve 659/48 without redoing the work?
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She should multiply the quotient by 48.
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4 years ago
The nature of a graph, which has an even degree and a positive leading coefficient will be
zaharov [31]

The nature of a graph, which has an even degree and a positive leading coefficient will be<u> up left, up right</u> position

<h3 /><h3>What is the nature of the graph of a quadratic equation?</h3>

The nature of the graphical representation of a quadratic equation with an even degree and a positive leading coefficient will give a parabola curve.

Given that we have a function f(x) = an even degree and a positive leading coefficient. i.e.

  • y = f(x) = 2x²+ 4

The domain of this function varies from -∞ < x < ∞ and the parabolic curve will be positioned on the upward left and upward right x-axis.

Learn more about the graph of a quadratic equation here:

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6 0
2 years ago
If you had carried out the algebra using variables before plugging numbers into your expressions, you would have found that (vf)
SashulF [63]

Answer:

Step-by-step explanation:

Volt is energy per electric charge

1V=1J/C

and the energy units in terms of meters, seconds and kilograms are:

1J= 1kg\frac{m^{2}}{s^{2}}

So the unit of volt is

1V= kg \frac{m^{2}}{Cs^{2}}

So the velocity expression (it can not be read completly) but i guess that it could be as follows

vf_{a} = -2\sqrt{\frac{q_{a}\Delta V}{m_{a}}}

So the unit analysis would be

vf_{a} = \sqrt{\frac{C kg\frac{m^{2}}{Cs^{2}}}{kg}}}

note that the coulomb unit of numerator is cancelled from the denominator. The same occurs for kg unit.

vf_{a} = \sqrt{\frac{m^{2}}{s^{2}}}

Applying square root

vf_{a} = \frac{m}{s}

7 0
3 years ago
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