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fiasKO [112]
3 years ago
12

What is the base 8 representation of the number 11100111

Mathematics
1 answer:
katovenus [111]3 years ago
6 0

If the given number is in base 2, that means

11100111₂ = 2⁷ + 2⁶ + 2⁵ + 2² + 2 + 1

8 = 2³, and so we have

11100111₂ = 2 • (2³)² + (2³)² + 2² • 2³ + 2² + 2 + 1

11100111₂ = 3 • 8² + 4 • 8 + 7

11100111₂ = 347₈

Because 8 is the 3rd power of 2, we can also split up the given number into block of length up-to 3, then convert each block directly into base 8:

11 100 111

11₂ = 2 + 1 = 3

100₂ = 2² = 4

111₂ = 2² + 2 + 1 = 7

so again we get 347₈.

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Answer:

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4 0
3 years ago
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A force of 12 lb is required to hold a spring stretched 8 in. beyond its natural length. How much work W is done in stretching i
sattari [20]

Answer:

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Step-by-step explanation:

Normal length of the spring = 8 in or \frac{8}{12} ft

= \frac{2}{3} ft

If the spring has been stretched to 11 inch then the stretched length of the spring is = 11 in

= \frac{11}{12} ft

Force applied to stretch the spring = 12 lb

By Hook's law,

F = kx [where k is the spring constant and x = length by which the spring is stretched]

12 = k(\frac{2}{3})

k = 18

Work done (W) to stretch the spring by \frac{11}{12} ft will be

W = \int\limits^\frac{11}{12} _0 {kx} \, dx

    = \int\limits^\frac{11}{12} _0 {(18x)} \, dx

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6 0
3 years ago
Using the geometric mean and Pythagorean theorem, calculate the values of the missing sides. Round your answers to the thousandt
Pachacha [2.7K]

Answer:

a = 9.849

b = 20.25

c = 491.03

Step-by-step explanation:

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(Hypotenuse)² = (Leg 1)² + (Leg 2)²

BC² = BD² + DC²

a² = 9² + 4²

a = \sqrt{(81+16)}

a = \sqrt{97}

a = 9.8489

a ≈ 9.849 units

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\frac{\text{DC}}{\text{BD}}=\frac{\text{BD}}{\text{AD}}

AD × DC = BD²

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b = \frac{81}{4}

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BY Pythagoras theorem in ΔADB,

AB² = AD² + BD²

c² = b² + 9²

c² = (20.25)² + 9²

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c = 491. 063 units

6 0
3 years ago
Find the mean of the following data set.<br><br> 42, 45, 58, 63
MakcuM [25]
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C ig.

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3 years ago
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