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Akimi4 [234]
3 years ago
15

#7 pls, i’m begging u :,)

Mathematics
1 answer:
777dan777 [17]3 years ago
6 0
B is the answer cudijfjdjsksks
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Write each equation in slope-intercept form of the equation of a line. Underline the slope and circle the y-intercept in each eq
VARVARA [1.3K]

\bf 3x + 4y - 12 = 0\implies 4y-12 = -3x\implies 4y=-3x+12 \\\\\\ y = \cfrac{-3x+12}{4}\implies y = \cfrac{-3x}{4}+\cfrac{12}{4} \\\\\\ y = \stackrel{\stackrel{m}{\downarrow }}{-\cfrac{3}{4}}x\stackrel{\stackrel{b}{\downarrow }}{+3} \qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}

5 0
3 years ago
Read 2 more answers
Find the equation of a line that passes through (0,0) that is perpendicular to 2x+3y=-6
Dovator [93]

The slope-intercept form of a line:

y=mx+b

m - slope

b - y-intercept

Convert 2x + 3y = -6 to the slope-intercet form:

2x+3y=-6         <em>subtract 2x from both sides</em>

3y=-2x-6         <em>divide both sides by 3</em>

y=-\dfrac{2}{3}x-2

Let k:y=m_1x+b_1 and l:y=m_2x+b_2

l\ \perp\ k\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}

We have m_1=-\dfrac{2}{3}

Therefore

m_2=-\dfrac{1}{-\frac{2}{3}}=\dfrac{3}{2}

We have the equation of a line:

y=\dfrac{3}{2}x+b

Put the coordinates of the point (0, 0) to the equation:

0=\dfrac{3}{2}(0)+b

0=b\to b=0

Answer: \boxed{y=\dfrac{3}{2}x}


8 0
3 years ago
Find dy/dx if y=(4x^2-5x)^8
musickatia [10]

dy/dx = 8(8x - 5)(4x² - 5x )^ 7

differentiate using the ' chain rule '

dy/dx = 8(4x² - 5x)^ 7 × d/dx (4x² - 5x)

         = 8(4x² - 5x)^ 7  × (8x - 5)

         = 8(8x - 5)(4x² - 5x)^{7}



6 0
3 years ago
Read 2 more answers
Help please i will give brainliest
tangare [24]

Answer:

7\geqr

Step-by-step explanation:

-1.3\geq2.9-0.6r

-2.9   -2.9

-4.2 ≥ -0.6r

/-0.6    /-0.6

7   ≥   r

8 0
3 years ago
S Rob and Bob together scored 88
Paul [167]
Rob scored 34 points. 88-54=34
3 0
3 years ago
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