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Rudiy27
2 years ago
11

Choose the appropriate software category for each specific application shown.

Computers and Technology
1 answer:
Tom [10]2 years ago
7 0
Python is the correct answer
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Hola buenas tardes, mi problema es el siguiente, en Word quiero alinear los párrafos por separado, pero, así lo sombree una line
Rudik [331]


Usa el botón Tab :)

6 0
3 years ago
In which decade did cell phones become available to the public?
JulijaS [17]

Answer:

1980s

Explanation:

Source:

https://www.cbc.ca/news/technology/5-major-moments-in-cellphone-history-1.1407352

6 0
3 years ago
Note: You can use a word document to write your answers and copy-paste your answer to the area specified. a. (5 points) Convert
MrMuchimi

Answer:

EA9_{16} = 3753

CB2_{16} = 3250

(1011 1110 1101 1011 1010)_2 = 781754

(1010 1000 1011 1000 1110 1101)_2 = 11057389

(1011 1110 1101 1011 1010)_2 = BEDBA

(1010 1000 1011 1000 1110 1101)_2 =  A8B8ED

74510_8= 221416

67210_8 = 203212

Explanation:

Solving (a): To base 10

(i)\ EA9_{16

We simply multiply each digit by a base of 16 to the power of their position.

i.e.

EA9_{16} = E * 16^2 + A * 16^1 + 9 * 16^0

EA9_{16} = E * 256 + A * 16 + 9 * 1

In hexadecimal

A = 10; E = 14

So:

EA9_{16} = 14 * 256 + 10 * 16 + 9 * 1

EA9_{16} = 3753

(ii)\ CB2_{16}

This gives:

CB2_{16} = C * 16^2 + B * 16^1 + 2 * 16^0

CB2_{16} = C * 256 + B * 16 + 2 * 1

In hexadecimal

C = 12; B =11

So:

CB2_{16} = 12 * 256 + 11 * 16 + 2 * 1

CB2_{16} = 3250

Solving (b): To base 10

(i)\ (1011 1110 1101 1011 1010)_2

We simply multiply each digit by a base of 2 to the power of their position.

i.e.

(1011 1110 1101 1011 1010)_2 = 1 * 2^{19} + 0 * 2^{18} + 1 * 2^{17} + 1 * 2^{16} +1 * 2^{15} + 1 * 2^{14} + 1 * 2^{13} + 0 * 2^{12} + 1 * 2^{11} + 1 * 2^{10} + 0 * 2^9 + 1 * 2^8 +1 * 2^7 + 0 * 2^6 + 1 * 2^5 + 1 * 2^4 + 1 * 2^3 + 0 * 2^2 + 1 * 2^1 + 0 * 2^0

(1011 1110 1101 1011 1010)_2 = 781754

(ii)\ (1010 1000 1011 1000 1110 1101)_2

(1010 1000 1011 1000 1110 1101)_2 = 1 * 2^{23} + 0 * 2^{22} + 1 * 2^{21} + 0 * 2^{20} +1 * 2^{19} + 0 * 2^{18} + 0 * 2^{17} + 0 * 2^{16} + 1 * 2^{15} + 0 * 2^{14} + 1 * 2^{13} + 1 * 2^{12} +1 * 2^{11} + 0 * 2^{10} + 0 * 2^9 + 0 * 2^8 + 1 * 2^7 + 1 * 2^6 + 1 * 2^5 + 0 * 2^4 + 1*2^3 + 1 * 2^2 + 0 * 2^1 + 1 * 2^0

(1010 1000 1011 1000 1110 1101)_2 = 11057389

Solving (c): To base 16

i.\ (1011 1110 1101 1011 1010)_2

First, convert to base 10

In (b)

(1011 1110 1101 1011 1010)_2 = 781754

Next, is to divide 781754 by 16 and keep track of the remainder

781754/16\ |\ 48859\ R\ 10

48859/16\ |\ 3053\ R\ 11

3053/16\ |\ 190\ R\ 13

190/16\ |\ 11\ R\ 14

11/16\ |\ 0\ R\ 11

Write out the remainder from bottom to top

(11)(14)(13)(11)(10)

In hexadecimal

A = 10; B = 11; C = 12; D = 13; E = 14; F = 15.

(11)(14)(13)(11)(10)=BEDBA

So:

(1011 1110 1101 1011 1010)_2 = BEDBA

ii.\ (1010 1000 1011 1000 1110 1101)_2

In b

(1010 1000 1011 1000 1110 1101)_2 = 11057389

Next, is to divide 11057389 by 16 and keep track of the remainder

11057389/16\ |\ 691086\ R\ 13

691086/16\ |\ 43192\ R\ 14

43192/16\ |\ 2699\ R\ 8

2699/16\ |\ 168\ R\ 11

168/16\ |\ 10\ R\ 8

10/16\ |\ 0\ R\ 10

Write out the remainder from bottom to top

(10)8(11)8(14)(13)

In hexadecimal

A = 10; B = 11; C = 12; D = 13; E = 14; F = 15.

(10)8(11)8(14)(13) = A8B8ED

So:

(1010 1000 1011 1000 1110 1101)_2 =  A8B8ED

Solving (d): To octal

(i.)\ 74510

Divide 74510 by 8 and keep track of the remainder

74510/8\ |\ 9313\ R\ 6

9313/8\ |\ 1164\ R\ 1

1164/8\ |\ 145\ R\ 4

145/8\ |\ 18\ R\ 1

18/8\ |\ 2\ R\ 2

2/8\ |\ 0\ R\ 2

Write out the remainder from bottom to top

74510_8= 221416

(ii.)\ 67210

Divide 67210 by 8 and keep track of the remainder

67210/8\ |\ 8401\ R\ 2

8401/8\ |\ 1050\ R\ 1

1050/8\ |\ 131\ R\ 2

131/8\ |\ 16\ R\ 3

16/8\ |\ 2\ R\ 0

2/8\ |\ 0\ R\ 2

Write out the remainder from bottom to top

67210_8 = 203212

8 0
3 years ago
Max shot a video with a digital camera. Where did the video files get stored in the camera?
Arturiano [62]

Answer:

In the memory sticks/cards of the digital camera

Explanation:

Many digital cameras come with removable storage cards in the form of memory cards, memory sticks and flask cards. Activities (pictures and videos) captured with these digital cameras are stored in these removable storage cards. These makes it easy for users to remove the storage cards and insert into other devices.

3 0
3 years ago
What are the benefits of writing functions that use parameters and return List 2 please and explain what is return
Ratling [72]

<u>Answer and explanation:</u>

There are many benefits of writing functions that use parameters and return. Some of them are:

1. Flexibility: With functions having parameters, several values of the parameters can be used at invocation time thereby making the application flexible. For example, given the following function in Java.

<em>public void showName(String name){</em>

<em>    System.out.println("Your name is " + name);</em>

<em>}</em>

To call this method (function), the programmer could use various values for the name parameter used in the function like so:

showName("John");

showName("Doe");

If the function didn't have a parameter, it is possible it will only print a hardcoded name every time the function is called.

2. Scope Control: When a function is allowed to return a value, it helps to work around scope issues since variables declared within a function are limited to that function and do not exist outside the function. This means that the values of these variables cannot be used anywhere else outside the function in which they are being declared. However, if the function returns a value, the value can be used anywhere else in the program.

For example:

<em>public String getDouble(int x){</em>

<em>    int y = x * 2</em>

<em>    return y;</em>

<em>}</em>

The function above returns twice the value of the argument supplied to it. Since the integer variable y is declared within the function, it's value cannot be used outside the function. However, since the value is being returned by the function, it could be used anywhere the function is being called. Thanks to the return keyword.

3 0
3 years ago
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