Answer:
1.82352941176
Step-by-step explanation:
;)
For the answer to the question above, I'll provide my solutions to my answers for the problem below.
(–2x3y2 + 4x2y3 – 3xy4) – (6x4y – 5x2y3 – y5)
(−2x3)(y2)+4x2y3+−3xy4+−1(6x4y)+−1(−5x2y3)+−1(−y5)
(−2x3)(y2)+4x2y3+−3xy4+−6x4y+5x2y3+y5
−2x3y2+4x2y3+−3xy4+−6x4y+5x2y3+y5
−2x3y2+4x2y3+−3xy4+−6x4y+5x2y3+y5
(−6x4y)+(−2x3y2)+(4x2y3+5x2y3)+(−3xy4)+(y5)
−6x4y+−2x3y2+9x2y3+−3xy4+y5
So the answer is,
= <span><span><span><span><span>−<span><span>6x4</span>y</span></span>−<span><span>2x3</span>y2</span></span>+<span><span>9x2</span>y3</span></span>−<span>3xy4</span></span>+y5</span>
I hope this helps
2(m-27n) this is the answer
Answer:
22.7604763 degrees
Step-by-step explanation:
Note that the answer is NOT 20 degrees.
She adjusted the ramp to half the original <em>incline</em>
Therefore we have tan 40 = x = 0.839099631.
We want an incline of y degrees where tan y = x/2 = 0.839099631/2 = 0.419549815
Taking the arctan of both sides, we get
y = arctan(0.419549815) = 22.7604763 degrees
Cosecant = hypotenuse / opposite side ( that is 1 / sine)
csc C = AC / 8
AC = sqrt (6^2 + 8^2) = sqrt 100 = 10
so cosecant of C is 10/8 = 1.25
