Answer:
Yes, they are both active transport processes.
Explanation:
Exocytosis describes the process of vesicles fusing with the plasma membrane and releasing their contents to the outside of the cell. Both endocytosis and exocytosis are active transport processes.
Answer:
selective and differential medium
.
Explanation:
Based on the information provided within the question it seems that this type of medium would be referred to as a selective and differential medium
. This is because such high NaCL levels are designed to stimulate and allow selective bacteria to grow, while also differential media because the fermented sugar is giving off a yellow halo which allows for the differentiate between the bacteria.
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I think the correct answer from the choices listed above is option A. Autotrophic protists are different from the heterotrophic protists in a sense that t<span>he autotrophic protists can photosynthesize, while the heterotrophic protists cannot. Hope this answers the question.</span>
Answer:
Thymidine dimers is likely to be repair as soon as it is originated but if left unrepaired then it causes frame shift mutations.
Explanation:
In case of Bacterium if UV irradiation induces covalent linkage of two thymidine present adjacently to each other or on a single strand to make thymidine dimers.
These either excised via DNA repair enzyme like Endonuclease V and the proof reading activity of DNA polymerase I enzyme help in incorporation of nucleotide by taking the unmutated original strand as a template.
These dimers if not excised before second round of replication than the sequence of newly synthesized strand will be altered. As DNA polymerase III enzyme read thymidine dimers as single thymidine nucleotide and incorporate only 1 adenine in the newly synthesizing complementary strand which results in frame shift mutations
It is the mutation in which reading frame of codons is shifted or altered due to deletion or addition of a single nucleotide.
