I don't know what your looking for, so be more specific, but I'm assuming your solving for x, so that's would be
x = -1
Answer:y=2/3x
Step-by-step explanation:
Answers:
Q: What is the most they could weigh together?
A: 0.74 kg
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Q: What is the least they could weigh together?
A: 0.62 kg
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Work Shown:
x = weight of first ball
y = weight of second ball
each ball has a weight range of 0.31 kg to 0.37 kg, so,
add straight down to get
which simplifies to
the two soccer balls have a weight range of 0.62 to 0.74, inclusive of both endpoints.
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Without using algebra, you basically just add the smallest the two weights could be (0.31) to itself to get 0.31+0.31 = 0.62 which represents the smallest the two weights combined can be. The same happens with the largest weight of 0.37 to get 0.37+0.37 = 0.74 as the max weight of both objects together.
The formula is:
Volume = Base area x height
We can plug in what you know, "h" represents height.
5/24 = 1/5 x h
Your goal is to isolate the variable, so divide each side by 1/5, which is the same as multiplying with 5.
5/1 x 5/24 = 5/1 x 1/5 x h
Simplify:
25/24 = 1 x h
1h is the same as h, so you've isolated the variable!
h = 25/24
25/24 is the same thing as 1 and 1/24
Thus, h = 1 and 1/24
Let me know if you need more help! :)
Answer:
<u>The correct answer is C. 129.</u>
Step-by-step explanation:
Let's recall that the Inscribed Quadrilateral Theorem states that a quadrilateral is inscribed in a circle if and only if the opposite angles are supplementary.
In the case of the inscribed quadrilateral ABCD in the graph attached, we have that:
m∠C= 51°, therefore its supplementary angle, ∠A, should be the difference between 180° and m∠C.
m∠C= 180° - m∠A
Replacing with the real values:
51 = 180 - m∠A
m∠A = 129°
<u>The correct answer is C. 129.</u>
