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schepotkina [342]
3 years ago
11

What is the product of 2x + y and 5x – y + 3?

Mathematics
1 answer:
Svet_ta [14]3 years ago
4 0

Answer: 10x² + 6x + 3xy + 3y – y²

Step-by-step explanation:

(2x + y)(5x – y + 3)

2x(5x – y + 3) + y(5x – y + 3)

10x² – 2xy + 6x + 5xy – y² + 3y

10x² + 6x + 3xy + 3y – y²

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Solve by factoring or finding square roots. -4x^2+3x = -1
zloy xaker [14]

Answer: (x+\frac{1}{4})(x-1)=0\\x_1=-\frac{1}{4}\\x_2=1

Step-by-step explanation:

1. To solve this problem the first thing you can do is divide both sides of the quadractic equation by -4, then:

x^{2}-\frac{3}{4}x+\frac{1}{4}=0

2. Now, to factor the quadratic equation you must find two numbers whose sum is -3/4 and the product is 1/4. These numbers are -1/4 and 1. Therefore, you have:

(x+\frac{1}{4})(x-1)=0

3. And the roots are:

 x_1=-\frac{1}{4}\\x_2=1

6 0
4 years ago
Read 2 more answers
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emmasim [6.3K]
17/5×5/4=17/4

Hope this helps
5 0
3 years ago
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Which equations are true? Choose all answers that apply: Choose all answers that apply: (Choice A) A -x +0+(- x) = 0−x+0+(−x)=0m
lora16 [44]

Answer:

(B)-x-(-x) =0

Step-by-step explanation:

<u>Option A</u>

Our equation is: -x +0+(- x) = 0

Left Hand Side:

-x +0+(- x) = -x-x=-2x

($Left Hand Side) $-2x\neq 0$ (Right Hand Side)

<u>Option B</u>

Our equation is: -x-(-x) =0

Left Hand Side:

-x-(-x) =-x+x=0

($Left Hand Side) 0 = 0 (Right Hand Side)

Therefore, the equation in Option B is true.

3 0
4 years ago
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Answer:

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Step-by-step explanation:

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3 years ago
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Taylor needs to rent a car while on vacation. The rental company charges $19.95, plus 17 cents for each mile driven. If Taylor o
shutvik [7]
This answer would be approximately 2 miles
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4 years ago
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