-7c , -6c , -1c , 4c , 0c , 0c , 3c work out the mean temperature

Mathematics

1 answer:

mixas84 [53]2 years ago

7 0

Step-by-step explanation:

(-7)+(-6)+(-1)=-14

(-14)-3=-11

-11÷7=-1.5714285714286 or -2 if you round too the tenths place

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A cereal mixture contains Almond, Wheat, and Corn in the ratio of 3:5:7. What amount of this mixture contains 9 kilograms of Alm

Mice21 [21]

The total cereal mixture is 45 kilograms

Solution:

Given that, cereal mixture contains Almond, Wheat, and Corn in the ratio of 3:5:7

Therefore,

Almond : Wheat : Corn = 3 : 5 : 7

Let the almond present be 3x

Let the wheat present be 5x

Let the corn present be 7x

Therefore,

Total cereal mixture = 3x + 5x + 7x

Total cereal mixture = 15x

Given that mixture contains 9 kg of almond

Almond = 9

We know that,

Almond present = 3x

3x = 9

x = 3

Therefore,

Total cereal mixture = 15x = 15(3) = 45

Thus total cereal mixture is 45 kilograms

3 0

3 years ago

Please answer correctly !!!!!!!!! Will Mark brainliest !!!!!!!!!!!!!

il63 [147K]

Answer:

$x=-\frac{-20+\sqrt{-20w+3600}}{10},\:x=-\frac{-20-\sqrt{-20w+3600}}{10}$

Step-by-step explanation:

$w=-5\left(x-8\right)\left(x+4\right)\\\mathrm{Expand\:}-5\left(x-8\right)\left(x+4\right):\quad -5x^2+20x+160\\w=-5x^2+20x+160\\Switch\:sides\\-5x^2+20x+160=w\\\mathrm{Subtract\:}w\mathrm{\:from\:both\:sides}\\-5x^2+20x+160-w=w-w\\Simplify\\-5x^2+20x+160-w=0\\Solve\:with\:the\:quadratic\:formula\\\mathrm{Quadratic\:Equation\:Formula:}\\\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\mathrm{For\:}\quad a=-5,\:b=20,\:c=160-w:\quad x_{1,\:2}=\frac{-20\pm \sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}\\x=\frac{-20+\sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}:\quad -\frac{-20+\sqrt{-20w+3600}}{10}\\x=\frac{-20-\sqrt{20^2-4\left(-5\right)\left(160-w\right)}}{2\left(-5\right)}:\quad -\frac{-20-\sqrt{-20w+3600}}{10}\\The\:solutions\:to\:the\:quadratic\:equation\:are\\x=-\frac{-20+\sqrt{-20w+3600}}{10},\:x=-\frac{-20-\sqrt{-20w+3600}}{10}$