Hudson and Katie are in a race and Hudson is running at 8-8 feet per sec. Katie gets 30 feet head start and is running in 6.3 fe
et per sec. How many sconds will it take until hudson and kaite to meet
1 answer:
Answer:
12s.
Step-by-step explanation:
Given:
Hudson's velocity, Vh = 8.8 ft/s
Katie's velocity, Vk = 6.3 ft/s
Kate's head start distance, Dk = 30 ft
From the above, Katie and Hudson meet at th = tk = t
But, Dk = Dh + 30
Velocity = Distance/time
t × Vk = Dk
t × Vh = Dh
t × Vk + 30 = Dk
t × Vk + 30 = Vh × t
6.3t + 30 = 8.8t
t = 30/2.5
= 12 s
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