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max2010maxim [7]
3 years ago
14

Determine the value of the first term and write a recursive definition for the following

Mathematics
1 answer:
Marysya12 [62]3 years ago
5 0
It is just counting by 5.
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You are scheduled to work 34 hours per week at your new job, where you earn $13.1 per
Lyrx [107]
13.1 an hour, 34 hours a week
13.1 x 34 = 445.4 a week
to find out how many weeks, divide 4300 and 445.4 which is 9.65 weeks, which is technically 10 weeks

it would take 10 weeks to earn 4300
6 0
1 year ago
The operator of a pumping station has observed that demand for water during early afternoon hours has an approximately exponenti
melomori [17]

Answer:

a) 0.1496 = 14.96% probability that the demand will exceed 190 cfs during the early afternoon on a randomly selected day.

b) Capacity of 252.6 cubic feet per second

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

f(x) = \mu e^{-\mu x}

In which \mu = \frac{1}{m} is the decay parameter.

The probability that x is lower or equal to a is given by:

P(X \leq x) = \int\limits^a_0 {f(x)} \, dx

Which has the following solution:

P(X \leq x) = 1 - e^{-\mu x}

The probability of finding a value higher than x is:

P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}

The operator of a pumping station has observed that demand for water during early afternoon hours has an approximately exponential distribution with mean 100 cfs (cubic feet per second).

This means that m = 100, \mu = \frac{1}{100} = 0.01

(a) Find the probability that the demand will exceed 190 cfs during the early afternoon on a randomly selected day. (Round your answer to four decimal places.)

We have that:

P(X > x) = e^{-\mu x}

This is P(X > 190). So

P(X > 190) = e^{-0.01*190} = 0.1496

0.1496 = 14.96% probability that the demand will exceed 190 cfs during the early afternoon on a randomly selected day.

(b) What water-pumping capacity, in cubic feet per second, should the station maintain during early afternoons so that the probability that demand will exceed capacity on a randomly selected day is only 0.08?

This is x for which:

P(X > x) = 0.08

So

e^{-0.01x} = 0.08

\ln{e^{-0.01x}} = \ln{0.08}

-0.01x = \ln{0.08}

x = -\frac{\ln{0.08}}{0.01}

x = 252.6

Capacity of 252.6 cubic feet per second

5 0
3 years ago
Which expression is equivalent to 11c-4c? A. 5c+2c B. 3c+7c
timurjin [86]
11c-4c = 7c
5c+2c= 7c
3c+7c= 10c

11c-4c= 5c+2c =A
4 0
3 years ago
What is the mass (in grams) of 8.11×1026 CO2 molecules?
Kobotan [32]

Answer:

<u>It</u><u> </u><u>is</u><u> </u><u>5</u><u>9</u><u>,</u><u>2</u><u>7</u><u>5</u><u>.</u><u>7</u><u>4</u><u> </u><u>grams</u>

Step-by-step explanation:

• Molecular mass of carbon dioxide

= (12 \times 1) + (16 \times 2) \\  = 12 + 32 \\  = 44 \: g

[ molar masses: C = 12 g, O = 16 g ]

• From avogadro's number, it says 1 mole contains 6.02 × 10^23 molecules or atoms.

But 1 mole is equivalent to its molar mass in terms of weight, therefore;

{ \sf{6.02 \times  {10}^{23}  \: molecules = 44 \: g }}\\  { \sf{8.11 \times  {10}^{26}  \: molecules =( \frac{8.11 \times  {10}^{26} }{6.02 \times  {10}^{23} }   \times 44) \: g}} \\  \\  = { \boxed{ \boxed{ \bf{59275.7 \:  \: g}}}}

6 0
3 years ago
Which of the following best describes the algebraic expression x/3 -15
Dennis_Churaev [7]

Answer:

A. A number divided by three minus fifteen.

7 0
3 years ago
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