Answer:
2
Step-by-step explanation:
Answer:
free throws = 6
2 points shots = 3
Step-by-step explanation:
To do this we will have 2 incognitas.
x = number of free throws
y = number of shots of 2 points
x(1) + y(2) = 12
he says he made twice as many free throws as 2 points
x = 2y
2y(1) + y(2) = 12
2y + 2y = 12
4y = 12
y = 12/4
y = 3
x = 2y
x = 2*3
x = 6
free throws = 6
2 points shots = 3
Answer:
13. c,
14. a.
Step-by-step explanation:
13. The length of a side PQ with coordinates of
P as (x,y) and Q as (w,z)
is: ![\sqrt{(x-w)^{2} +(y-z)^{2} }](https://tex.z-dn.net/?f=%5Csqrt%7B%28x-w%29%5E%7B2%7D%20%2B%28y-z%29%5E%7B2%7D%20%7D)
- so, the length of the side AB =
![\sqrt{(5-5)^{2}+(-2+7)^{2} } =\sqrt{0^{2}+5^{2} } =5](https://tex.z-dn.net/?f=%5Csqrt%7B%285-5%29%5E%7B2%7D%2B%28-2%2B7%29%5E%7B2%7D%20%20%7D%20%3D%5Csqrt%7B0%5E%7B2%7D%2B5%5E%7B2%7D%20%20%7D%20%3D5)
![\sqrt{(5-1)^{2}+(-7+2)^{2} } =\sqrt{(4)^{2}+(-5)^{2} } =\sqrt{4^{2}+5^{2} }](https://tex.z-dn.net/?f=%5Csqrt%7B%285-1%29%5E%7B2%7D%2B%28-7%2B2%29%5E%7B2%7D%20%20%7D%20%3D%5Csqrt%7B%284%29%5E%7B2%7D%2B%28-5%29%5E%7B2%7D%20%20%7D%20%3D%5Csqrt%7B4%5E%7B2%7D%2B5%5E%7B2%7D%20%20%7D)
![\sqrt{(5-1)^{2} +(-2+2)^{2} } =\sqrt{4^{2} } =4](https://tex.z-dn.net/?f=%5Csqrt%7B%285-1%29%5E%7B2%7D%20%2B%28-2%2B2%29%5E%7B2%7D%20%7D%20%3D%5Csqrt%7B4%5E%7B2%7D%20%7D%20%3D4)
now, the easiest one will be when the vertices are on the coordinate axes.
- so, option c will be the most appropriate one.
14. If u see the figure clearly, the lines l and FH are parallel.
the parallel postulate, i.e, the alternate interior angles will always be congruent.
- here, the alternate interior angles are angle1 and angle4.
- therefore to prove this step, he used parallel postulate as a reason.
- so, the correct option is "a"
Answer: x=2
step by step explanation:
Answer:
option a) 30 : 19
Step-by-step explanation:
![Length = 7 \frac{1}{2} = \frac{15}{2}\\\\Width = 4\frac{3}{4} = \frac{19}{4}](https://tex.z-dn.net/?f=Length%20%3D%207%20%5Cfrac%7B1%7D%7B2%7D%20%3D%20%5Cfrac%7B15%7D%7B2%7D%5C%5C%5C%5CWidth%20%3D%204%5Cfrac%7B3%7D%7B4%7D%20%3D%20%5Cfrac%7B19%7D%7B4%7D)
<em><u>Ratio of length to width:</u></em>
<em><u></u></em>
![=\frac{\frac{15}{2}}{\frac{19}{4}}\\\\=\frac{15}{2 } \times \frac{4}{19}\\\\=15\times \frac{2}{19}\\\\=\frac{30}{19}\\\\30 : 19](https://tex.z-dn.net/?f=%3D%5Cfrac%7B%5Cfrac%7B15%7D%7B2%7D%7D%7B%5Cfrac%7B19%7D%7B4%7D%7D%5C%5C%5C%5C%3D%5Cfrac%7B15%7D%7B2%20%7D%20%5Ctimes%20%5Cfrac%7B4%7D%7B19%7D%5C%5C%5C%5C%3D15%5Ctimes%20%5Cfrac%7B2%7D%7B19%7D%5C%5C%5C%5C%3D%5Cfrac%7B30%7D%7B19%7D%5C%5C%5C%5C30%20%3A%2019)