The question is incomplete. Here is the complete question.
Find the measurements (the lenght L and the width W) of an inscribed rectangle under the line y = -
x + 3 with the 1st quadrant of the x & y coordinate system such that the area is maximum. Also, find that maximum area. To get full credit, you must draw the picture of the problem and label the length and the width in terms of x and y.
Answer: L = 1; W = 9/4; A = 2.25;
Step-by-step explanation: The rectangle is under a straight line. Area of a rectangle is given by A = L*W. To determine the maximum area:
A = x.y
A = x(-
)
A = -
To maximize, we have to differentiate the equation:
= 
(-)
= -3x + 3
The critical point is:
= 0
-3x + 3 = 0
x = 1
Substituing:
y = -x + 3
y = -.1 + 3
y = 9/4
So, the measurements are x = L = 1 and y = W = 9/4
The maximum area is:
A = 1 . 9/4
A = 9/4
A = 2.25
Answer:45 * t = 2.5 * (1-t)...the equation will have one solution.
Step-by-step explanation:
For this case, the first thing you should know is:
d: v * t
Where,
d: distance
v: speed
t: time
To go to school by bus we have:
d = 45 * t
To return from school we have:
d = 2.5 * (1-t)
how the distance is the same:45 * t = 2.5 * (1-t)
John's function : y = 3.5x - 4
Penny's function : y = 3x + 4
C. John's function has a greater rate of change, because 3.5 > 3
Answer:
add both x coordinates and divide them by 2.
add both y coordinates and divide them by 2.
Now final product should be (x,y)
Step-by-step explanation:
Example.
let's take 2 points:
(2,5) and (7, 9)
let's add both x coordinates.
2+7 = 9
now add both y coordinates.
5+9 = 14
Now divide both by 2.
Final answer should be (4.5, 7) = this is your midpoint
