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3 years ago

If there are 67 cherries on one tree how many cherries are on 345 trees.

Mathematics

1 answer:

Mashutka [201]3 years ago

8 0

Answer:

If we assume that each tree will produce the same number of cherries then the answer is 23,115

Step-by-step explanation:

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Use DeMoivre's Theorem to find the following. Write your answer in<br> standard form.

valina [46]

Answer:

Option C.

Step-by-step explanation:

The given expression is

$\left(\sqrt{2}cis \dfrac{9\pi}{20}\right)^5$

It can be rewritten as

$\left(\sqrt{2}\cos \dfrac{9\pi}{20}+i\sin\dfrac{9\pi}{20}\right)^5$

According to De moivre's Theorem:

$[r(\cos\theta+i\sin \theta)]^n=r^n(\cos n\theta +i\sin n\theta)$

Using De moivre's Theorem, we get

$(\sqrt{2})^5\left(\cos \dfrac{9\pi\times 5}{20}+i\sin\dfrac{9\pi\times 5}{20}\right)$

$=4\sqrt{2}\left(\cos \dfrac{9\pi}{4}+i\sin\dfrac{9\pi}{4}\right)$

$=4\sqrt{2}\left(\cos (2\pi +\dfrac{\pi}{4})+i\sin (2\pi+\dfrac{\pi}{4})\right)$

$=4\sqrt{2}\left(\cos \dfrac{\pi}{4}+i\sin \dfrac{\pi}{4}\right)$

$=4\sqrt{2}\left(\dfrac{1}{\sqrt{2}}+i\dfrac{1}{\sqrt{2}}\right)$

$=4+4i$

Therefore, the correct option is C.

5 0

3 years ago

What is the slope of the line described by the equation below?

exis [7]

Answer:

D :)

Step-by-step explanation:

8 0

3 years ago

Determine the area of the given figure:<br><br> .

Aneli [31]

Which given figure ???

5 0

3 years ago

Can you help me with the Anabella question pls

SVETLANKA909090 [29]

Answer:

-260

Step-by-step explanation:

you would add -60, -85, and -115 together to get -260

best of luck!

8 0

3 years ago

Read 2 more answers

Express the confidence interval 0.319 < p < 0.488 in the form of p ± E.

KengaRu [80]

Answer:

$0.4035+/-0.0845$

Step-by-step explanation:

The fundamental step would be to determine the values of p and E which i believe is the margin of error in this case. Consider the following two equations;

$p-E=0.319\\p+E=0.488$

We simply add the two equations and solve for p;

$2p=0.807\\p=0.4035$

We then substitute this value of p in either equation and solve for E;

$0.4035-E=0.319\\E=0.0845$

Since we have both p and E, the confidence interval can thus be written as;

$0.4035+/-0.0845$

8 0

3 years ago