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charle [14.2K]
3 years ago
12

Write an algebraic expression for the word expression. The product of 8 and z

Mathematics
1 answer:
Law Incorporation [45]3 years ago
5 0

Answer:

8z

Step-by-step explanation:

have a wonderful day....

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Asking for a friend. Someone, please help out. Will give 15 points for it and brainliest when possible.
Afina-wow [57]

Answer:

A reflected across the x-axis followed by a transferred or whatever it called(start with a t)across the y-axis

Step-by-step explanation:

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SOMEONE HELP I DONT KNOW WHAT THE HECK IM DOING (7th grade)
m_a_m_a [10]

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Step-by-step explanation:

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For this problem, you can start by taking the 35 and dividing it by 5 to get 7. Then you need to take 300 and divide that by 5 to get the right proportions. Then you can take your new number from 300 and divide that by 7, and you should not be on the right path because I'm probably an idiot.

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3 years ago
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Answer:

2020 edge

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3 years ago
Two of the angles in a triangle measure 57º and 25°. What must be the measure of the
ira [324]

The measure of the third angle in the triangle is 104 degrees

<h3>How to determine the measure of the third angles?</h3>

Let the three angles in the triangle be x, y and z.

Such that:

x = 51

y = 25

The sum of angles in a triangle is 180 degrees.

So, we have:

x + y  + z = 180

Substitute known values

51 + 25 + z = 180

Evaluate the sum

76 + z = 180

Subtract 76 from both sides

z = 104

Hence, the measure of the third angle is 104 degrees

Read more about triangles at:

brainly.com/question/21735282

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5 0
2 years ago
X2 - 6x + 12 and y = 2x - 4, algebraically are
olga_2 [115]

<em><u>The solution is (4, 4)</u></em>

<em><u>Solution:</u></em>

<em><u>Given system of equations are:</u></em>

y = x^2 - 6x + 12 ------ eqn\ 1\\\\y = 2x - 4 ---------- eqn\ 2

<em><u>Substitute eqn 2 in eqn 1</u></em>

x^2 - 6x + 12 = 2x - 4

Make the right side of equation 0

x^2 - 6x + 12 - 2x + 4 = 0\\\\x^2 -8x + 16 = 0

<em><u>Solve by quadratic equation</u></em>

\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\mathrm{For\:}\quad a=1,\:b=-8,\:c=16:\\\\x=\frac{-\left(-8\right)\pm \sqrt{\left(-8\right)^2-4\cdot \:1\cdot \:16}}{2\cdot \:1}\\\\x=\frac{-\left(-8\right)\pm \sqrt{0}}{2\cdot \:1}\\\\x = \frac{8}{2}\\\\x = 4

<em><u>Substitute x = 4 in eqn 2</u></em>

y = 2(4) - 4

y = 8 - 4

y = 4

Thus solution is (4, 4)

5 0
3 years ago
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