Answer:
[g+2/3g-1] ÷ [g^2+2g/6g+2]
g+2/3g-1 × 6g+2/g^2+2g
g+2/3g-1 × 2(3g +1)/g(g+2)
1/ 3g-1 × 2(3g+1)/g
2(3g +1)÷ g(3g-1)
6g+2 ÷[3g^2-g]
9.75-3.50=2.50x
6.25=2.50x
6.25÷2.5=2.50x÷2.5
2.5=x
Answer:
Answer: The mean increases by 3
Step-by-step explanation:
The original data set is
{50, 76, 78, 79, 79, 80, 81, 82, 82, 83}
The outlier is 50 because it is not near the group of values from 76 to 83 which is where the main cluster is.
The original mean is M = (50+76+78+79+79+80+81+82+82+83)/10 = 77
If we take out the outlier 50, the new mean is N = (76+78+79+79+80+81+82+82+83)/9 = 80
So in summary so far
old mean = M = 77
new mean = N = 80
The difference in values is N-M = 80-77 = 3
So that's why the mean increases by 3
Answer:
I don't see the photo. Can't help OOF
Step-by-step explanation:
Answer:
B. The number of navy tiles Mr langley purchased is 2.5 times the number of yellow purchased
Step-by-step explanation:
2.5x40=100
