The amounts for each donut are given as follows:
<h3>How to obtain the amounts?</h3>
The amounts for each donut are found applying the proportion, multiplying the decimal equivalent of each percentage by the total number of donuts.
From the problem, the total number of donuts is given as follows:
100 donuts.
The percentages of each type of donuts are given as follows:
The decimal equivalent of each percentage is given as follows:
Hence the amounts are given as follows:
- Strawberry: 15, as 0.15 x 100 = 15.
- Chocolate: 45, as 0.45 x 100 = 45.
- Sprinkle: 40, as 0.4 x 100 = 40.
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Answer:
0.87 > 0.17
3.97 < 6.63
8.04 < 8.9
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Step-by-step explanation:
Answer:
75 Degrees
Step-by-step explanation:
Answer:
The proportion of infants with birth weights between 125 oz and 140 oz is 0.1359 = 13.59%.
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:

The proportion of infants with birth weights between 125 oz and 140 oz is
This is the pvalue of Z when X = 140 subtracted by the pvalue of Z when X = 125. So
X = 140



has a pvalue of 0.9772
X = 125



has a pvalue of 0.8413
0.9772 - 0.8413 = 0.1359
The proportion of infants with birth weights between 125 oz and 140 oz is 0.1359 = 13.59%.