A box of chalk contains 10 pieces. how many pieces of chalk are in 40 boxes
2 answers:
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Answer:
Step-by-step explanation:
It is given that in △ABC, ∠ABC=90°, BH is an altitude and AB=9 and AC=12, thus using the Pythagoras theorem in △ABC, we get
Now, From ΔABC and ΔHBC, we have
∠ABC=∠BHC(each90)
∠ACB=∠HCB (Common)
By AA similarity, ΔABC is similar to ΔHBC.
Thus, using the similarity condition, we get
Answer:
The height of the ball after 3 secs of dropping is 16 feet.
Step-by-step explanation:
Given:
height from which the ball is dropped = 160 foot
Time = t seconds
Function h(t)=160-16t^2.
To Find:
High will the ball be after 3 seconds = ?
Solution:
Here the time ‘t’ is already given to us as 3 secs.
We also have the relationship between the height and time given to us in the question.
So, to find the height at which the ball will be 3 secs after dropping we have to insert 3 secs in palce of ‘t’ as follows:
h(3)=160-144
h(3)=16
Therefore, the height of the ball after 3 secs of dropping is 16 feet.