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2 years ago

10

11 Megan has $500 in her savings account. The interest rate is 7%, which is not compounded. How much money in dollars) will she

have in her account after 5 years? Write the correct
answer.

1 answer:

Ivenika [448]2 years ago

8 0

Answer:

701

Step-by-step explanation:

At the end of 5 years, your savings will have grown to $701.

You will have earned in $201 in interest.

answer.

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Which of the binomials below is a factor of this trinomial?

Tamiku [17]

Lets set our x's apart first, the 5 can only be multiplied by 1 and 5 to get it so lets put a 5 in one side and a 1 in the other... it should look like (5x )(1x )
now we have a postive in the first term and a negative in the second, this means that there will be a positive and a negative sign... now lets see what can be multiplied by 50 that can add to be 15.. lets try 25 times 2 it gives you 50 but lets check if it gives you 15 in the middle,,lets set it up like this (5x+25)(1x-2) if you multiply these will you get 5x2+15x-50?? yes you will!! so which of these factors are alike to your answer?? well the only one would be (x-2), this means your answer would be letter C

Hope this helps

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3 years ago

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Which statement best describes the association between variable X and variable Y?

postnew [5]

I think its A perfect negative association

perfect because it is in a straight order and negative because its slope is negative

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3 years ago

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X+y=5 <br> 3x-y=7 <br> solve this equation

motikmotik

The intercepts for x+y=5
X= (5,0)
Y= (0,5)
Slope is 3 and y intercept is (0,7)

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1 year ago

What is the probability of drawing the compliment of a king or a

inna [77]

Answer:

The probability of drawing the compliment of a king or a queen from a standard deck of playing cards = 0.846

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Let 'S' be the sample space associated with the drawing of a card

n (S) = 52C₁ = 52

Let E₁ be the event of the card drawn being a king

$n( E_{1} ) = 4 _{C_{1} } = 4$

Let E₂ be the event of the card drawn being a queen

$n( E_{2} ) = 4 _{C_{1} } = 4$

But E₁ and E₂ are mutually exclusive events

since E₁ U E₂ is the event of drawing a king or a queen

<u><em>step(ii):-</em></u>

The probability of drawing of a king or a queen from a standard deck of playing cards

P( E₁ U E₂ ) = P(E₁) +P(E₂)

$= \frac{4}{52} + \frac{4}{52}$

P( E₁ U E₂ ) = $\frac{8}{52}$

<u><em>step(iii):-</em></u>

The probability of drawing the compliment of a king or a queen from a standard deck of playing cards

$P(E_{1}UE_{2}) ^{-} = 1- P(E_{1} U E_{2} )$

$P(E_{1}UE_{2}) ^{-} = 1- \frac{8}{52}$

$P(E_{1}UE_{2}) ^{-} = \frac{52-8}{52} = \frac{44}{52} = 0.846$

<u><em>Conclusion</em></u>:-

The probability of drawing the compliment of a king or a queen from a standard deck of playing cards = 0.846

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2 years ago

Please help I’ll give brainliest and 20 extra points!

Anastasy [175]

Answer:

<em>42/63 = .6 repeating</em>

<em>30/38 = .625</em>

<em>36/60 = .6</em>

<em>57/90 = .63 repeating</em>

Step-by-step explanation:

Nd if I'm wrong then the 2nd nd 3rd one are switched

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2 years ago