Question

(3x−2formula">+(2x−4$)^{2}$ =3
please solve

Answer 1

Infinite solutions (extra characters)

Answer 2

Question: (3x-2)² + (2x-4)² = 3

Answer:

When squaring things, we are just multiplying it by itself (a² = a x a). When squaring brackets, it’s the same rule:

Therefore:

(3x-2)² = (3x-2)(3x-2)
(2x-4)² = (2x-4)(2x-4)

And using this skill we get:

(3x-2)(3x-2) + (2x-4)(2x-4) = 3

Using FOIL:

9x²-6x-6x+4 + 4x²-8x-8x+16 = 3

Simplify:

13x²-28x+20 = 3

Take -20 off from both sides:

13x²-28x = -17

There’s your answer!

I hope this made sense, if you have any questions or you think I made a mistake somewhere please let me know!

:)