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3 years ago

An integer added to an integer is an integer true sometimes or never true

Mathematics

2 answers:

lapo4ka [179]3 years ago

8 0

Answer:

If an integer is added to another integer, it remains an integer, or something else, like a whole number.

Answer: TRUE SOMETIMES

Step-by-step explanation:

please mark the other answer brainliest, not this one .

Hope this helps :)

Archy [21]3 years ago

6 0

Answer: true sometimes

Step-by-step explanation:

The main difference between integers and whole numbers is the fact that integers can be a negative value while whole numbers cannot be negative.

If an integer is added to an integer, it can become an integer or a whole number.

I hope this is clear, please mark as brainliest answer

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Please help! show explanation please

Rudiy27

Hey use photo math is gonna help you a lot

4 0

1 year ago

Can you please help me?

yan [13]

Answer:

-3, -4, -4, 0, 16, 64, 192.

Step-by-step explanation:

I don't know for sure if this is correct, but when i did it theses are the answers i got. You do y=8*2^x. Meaning you substitute the x for the x values such as -3, -2, and -1.

Also if you have one there's a setting you can go to on an actual calculator and type in this on a Y/X chart. I didn't use one this time because i don't have one, but thought you'd find that information useful.

6 0

2 years ago

What is the distance between the points (5.-18) and (8,

romanna [79]

Answer:

$\sqrt{10}$

Step-by-step explanation:

The horizontal distance from points (5,-18) and (8,-17) is 3 because it is 3 units from 5 to 8. The vertical distance is 1 since it is one unit from -18 to -17. Now we can use the equation $a^{2}+b^{2}=c^{2}$ where a=3 and b=1 and c is the distance that you are looking for:

$a^{2} +b^{2} =c^{2}\\3^{2} +1^{2} =c^{2}\\9+1=c^{2}\\10=c^{2}\\\sqrt{10}=c$

8 0

2 years ago

Read 2 more answers

Say you're playing three-card poker; that is, you're dealt three cards in a row at random from a standard deck of 52 cards. What

Brums [2.3K]

Answer:

Step-by-step explanation:

Given

There are 52 cards in total

there are total of 13 pairs of same cards with each pair containing 4 cards

Probability of getting a pair or three of kind card=1-Probability of all three cards being different

Probability of selecting all three different cards can be find out by selecting a card from first 13 pairs and remaining 2 cards from remaining 12 pairs i.e.

$=\frac{52\times 48\times 44}{52\times 51\times 50}$

for first card there are 52 options after choosing first card one pair is destroyed as we have to select different card .

For second card we have to select from remaining 12 pairs i.e. 48 cards and so on for third card.

Required Probability is $=1-\frac{52\times 48\times 44}{52\times 51\times 50}$

$=\frac{22776}{132600}$

7 0

2 years ago

There are 8 tennis players in a round robin tournament, which means each team will play every other team once. How many matches

Aliun [14]

<h3>Answer: 28</h3>

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Explanation:

Method 1

Imagine a table with 8 rows and 8 columns to represent all possible match-ups. You can actually draw out this table or just think of it as a thought experiment.

There are 8*8 = 64 entries in the table. Along the northwest diagonal, we have each team pair up with itself. This is of course silly and impossible. We cross off this entire diagonal so we drop to 64-8 = 56 entries.

Then notice that the lower left corner is a mirror copy of the upper right corner. A match-up like AB is the same as BA. So we must divide by 2 to get 56/2 = 28 different matches.

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Method 2

There are 8 selections for the first slot, and 8-1 = 7 selections for the second slot. We have 8*7 = 56 permutations and 56/2 = 28 combinations.

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Method 3

Use the nCr combination formula with n = 8 and r = 2

$n C r = \frac{n!}{r!(n-r)!}\\\\8 C 2 = \frac{8!}{2!*(8-2)!}\\\\8 C 2 = \frac{8!}{2!*6!}\\\\8 C 2 = \frac{8*7*6!}{2!*6!}\\\\ 8 C 2 = \frac{8*7}{2!}\\\\ 8 C 2 = \frac{8*7}{2*1}\\\\ 8 C 2 = \frac{56}{2}\\\\ 8 C 2 = 28\\\\$

There are 28 combinations possible. Order doesn't matter (eg: match-up AB is the same as match-up BA).

Notice how the (8*7)/2 expression is part of the steps shown above in the nCr formula.

7 0

1 year ago