Let U = {t,u,v,w.x,y,z). A = {w.y}, B = {v,w}, C = {t.x.v}, and D = {v.z.x.t,w}. Tell whether the statement below is true or fal
Licemer1 [7]
Given
Let U = {t,u,v,w.x,y,z). A = {w.y}, B = {v,w}, C = {t.x.v}, and D = {v.z.x.t,w}. Tell whether the statement below is true or false. U is the universal set.
Solution
A universal set (usually denoted by U) is a set which has elements of all the related sets, without any repetition of elements.Say if A and B are two sets, such as A = {1,2,3} and B = {1,a,b,c}, then the universal set associated with these two sets is given by U = {1,2,3,a,b,c}.
Since, set A, Set B, Set C and Set D are subset of Set U
Therfore, it is true Set
<h3>
Answer: A. 18*sqrt(3)</h3>
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Explanation:
We'll need the tangent rule
tan(angle) = opposite/adjacent
tan(R) = TH/HR
tan(30) = TH/54
sqrt(3)/3 = TH/54 ... use the unit circle
54*sqrt(3)/3 = TH .... multiply both sides by 54
(54/3)*sqrt(3) = TH
18*sqrt(3) = TH
TH = 18*sqrt(3) which points to <u>choice A</u> as the final answer
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An alternative method:
Triangle THR is a 30-60-90 triangle.
Let x be the measure of side TH. This side is opposite the smallest angle R = 30, so we consider this the short leg.
The hypotenuse is twice as long as x, so TR = 2x. This only applies to 30-60-90 triangles.
Now use the pythagorean theorem
a^2 + b^2 = c^2
(TH)^2 + (HR)^2 = (TR)^2
(x)^2 + (54)^2 = (2x)^2
x^2 + 2916 = 4x^2
2916 = 4x^2 - x^2
3x^2 = 2916
x^2 = 2916/3
x^2 = 972
x = sqrt(972)
x = sqrt(324*3)
x = sqrt(324)*sqrt(3)
x = 18*sqrt(3) which is the length of TH.
A slightly similar idea is to use the fact that if y is the long leg and x is the short leg, then y = x*sqrt(3). Plug in y = 54 and isolate x and you should get x = 18*sqrt(3). Again, this trick only works for 30-60-90 triangles.
Answer:
a. P= 0.6364
b. P = 0.3636
c. Q = $21.25
d. P = 0.5
Step-by-step explanation:
given data
value of a stock varies = $13 to $24
solution
P (stock value is more than $17)
P = 
P = 
P = 0.6364
and
P (value of the stock is between $17 and $21)
P = 
P = 
P = 0.3636
and
Let the upper quartile be Q
(24 - Q) = 2.75
so
Q = $21.25
and
P(X > 20 | X > 16)
P = 
P = 
P = 0.5
X+y+z=92
y=3x
z=2x-10
subsitute
x+3x+2x-10=92
6x-10=92
add 10 to both sdies
6x=102
divide by 6
x=17
subsitute
y=3x
y=3(17)
y=51
z=2x-10
z=2(17)-10
z=34-10
z=24
x=17
y=51
z=24
the numbers are 17,51,24
Answer:
Year 10 Interactive Maths - Second Edition
Problem Solving
Linear equations are often used to solve practical problems that have an unknown quantity. We use a suitable pronumeral to represent the unknown quantity, translate the information given in the problem into an equation, and then solve the equation using the skills acquired earlier in this chapter.
Example 11
If a number is increased by 8, the result is 25. Find the number.
Solution:
Let x be the number. Increasing x by 8 gives x + 8, which we are told is 25. Therefore, x + 8 = 25. Subtract 8 from both sides to find x = 17. So, the number is 17.
Step-by-step explanation:
I hope this helps!!!
