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1 answer:
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Answer: approximately 49 feets
Step-by-step explanation:
The diagram of the tree is shown in the attached photo. The tree fell with its tip forming an angle of 36 degrees with the ground. It forms a right angle triangle,ABC. Angle C is gotten by subtracting the sum of angle A and angle B from 180(sum of angles in a triangle is 180 degrees).
To determine the height of the tree, we will apply trigonometric ratio
Tan # = opposite/ adjacent
Where # = 36 degrees
Opposite = x feets
Adjacent = 25 feets
Tan 36 = x/25
x = 25tan36
x = 25 × 0.7265
x = 18.1625
Height of the tree from the ground to the point where it broke = x = 18.1625 meters.
The entire height of the tree would be the the length of the fallen side of the tree, y + 18.1625m
To get y, we will use Pythagoras theorem
y^2 = 25^2 + 18.1625^2
y^2 = 625 + 329.88
y^2 = 954.88
y = √954.88 = 30.9 meters
Height of the tree before falling was
18.1625+30.9 = 49.0625
The height of the tree was approximately 49 feets
Answer:
d = 234.6 m
Step-by-step explanation:
You can consider a system of coordinates with its origin at the beginning of the walk of the student.
When she start to walk, she is at (0,0)m. After her first walk, her coordinates are calculated by using the information about the incline and the distance that she traveled:
she is at the coordinates (52.97 , 28.16)m.
Next, when she walks 180m to the east, her coordinates are:
(52.97+180 , 28.16)m = (232.97 , 28.16)m
To calculate the distance from the final point of the student to the starting point you use the Pythagoras generalization for the distance between two points:
The displacement of the student on her complete trajectory was of 234.6m