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Ulleksa [173]
3 years ago
8

Outline the process for Inscribing an equilateral triangle in a circle. Perform the construction in GeoGebra, and take a

Mathematics
1 answer:
mezya [45]3 years ago
5 0

Answer:

I don't use Geogebra, but the following procedure should work.

Step-by-step explanation:

Construct a circle A with point B on the circumference.

  1. Use the POINT and SEGMENT TOOLS to create a circle with centre B and radius BA.
  2. Use the POINT tool to mark points D and E where the circles intersect.
  3. Use the SEGMENT tool to draw segments from C to D, C to E, and D to E.

You have just created equilateral ∆CDE inscribed in circle A.

 

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6. Which of the following function pairs are inverses?
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Find the surface area of a sphere that has a volume of 288 cu. in.
LenKa [72]

The formula of a volume of a sphere:

V=\dfrac{4}{3}\pi R^3

R - radius

We have the volume = 288 in³. Substitute:

\dfrac{4}{3}\pi R^3=288\qquad\text{multiply both sides by 3}\\\\4\pi R^3=864\qquad\text{divide both sides by}\ 4\pi\\\\R^3=\dfrac{216}{\pi}\to R=\sqrt[3]{\dfrac{216}{\pi}}\\\\R=\dfrac{\sqrt[3]{216}}{\sqrt[3]{\pi}}\\\\R=\dfrac{6}{\sqrt[3]{\pi}}\ in

The formula of a surface area of a sphere:

S.A.=4\pi R^2

Substitute:

S.A.=4\pi\left(\dfrac{6}{\sqrt[3]{\pi}}\right)^2=4\pi\cdot\dfrac{6^2}{\sqrt[3]{\pi^2}}=\dfrac{4\pi\cdot36}{\sqrt[3]{\pi^2}}=\dfrac{144\pi}{\sqrt[3]{\pi^2}}\\\\S.A.=\dfrac{144\pi}{\sqrt[3]{\pi^2}}\cdot\dfrac{\sqrt[3]{\pi}}{\sqrt[3]{\pi}}=\dfrac{144\pi\sqrt[3]{\pi}}{\sqrt[3]{\pi^3}}=\dfrac{144\pi\sqrt[3]{\pi}}{\pi}=\boxed{144\sqrt[3]{\pi}\ in^2}

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3 years ago
When four basketball players are about to have a​ free-throw competition, they often draw names out of a hat to randomly select
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The total number of possibilities of drawing their names is given by permutation.

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The total possibility of drawing their names in alphabetical is only 1.

 

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P = 1 / 24

P = 0.0417

 

<span>Therefore there is about 4.17% chance that it will be in alphabetical order</span>

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